Tried to replace this with this, but results are the same
temp1 = p.children[1] temp2 = p.children[2] p.children[2] = temp1 p.children[1] = temp2 From: sqlalchemy@googlegroups.com [mailto:sqlalchemy@googlegroups.com] On Behalf Of Michael Bayer Sent: Tuesday, January 08, 2013 2:23 AM To: sqlalchemy@googlegroups.com Subject: Re: [sqlalchemy] Strange behaviour while trying to swap related records, or am I doing it wrong? On Jan 7, 2013, at 7:05 PM, Alexey Vihorev wrote: p.children[1], p.children[2] = p.children[2], p.children[1] print(p.children) #prints [Mary, Kenny, John] yeah, without looking too deeply I'm fairly certain this is this trac ticket: http://www.sqlalchemy.org/trac/ticket/1103 basically would add a good chunk of complexity and overhead to the list instrumentation. this is a "blue sky" ticket for that reason. For now you'd need to just assign to an intermediary variable and do one assignment at a time. -- You received this message because you are subscribed to the Google Groups "sqlalchemy" group. To post to this group, send email to sqlalchemy@googlegroups.com. To unsubscribe from this group, send email to sqlalchemy+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/sqlalchemy?hl=en. -- You received this message because you are subscribed to the Google Groups "sqlalchemy" group. To post to this group, send email to sqlalchemy@googlegroups.com. To unsubscribe from this group, send email to sqlalchemy+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/sqlalchemy?hl=en.
