On Feb 11, 2013, at 5:45 PM, Matthew Rich <matt...@matthewrich.com> wrote:
> > And I want to achieve SQL that basically looks like this (IE, show me the > schools with more than one coordinator): > SELECT s.Id, COUNT(c.Id) > FROM School s > INNER JOIN SchoolCoordinator sc ON s.Id = sc.SchoolId > INNER JOIN Coordinator c ON sc.CoordinatorId = c.Id > GROUP BY s.Id > HAVING COUNT(c.Id) > 1 > > The HAVING example in the query object documentation is for a one-to-many > relationship and seems pretty straightforward. None of the incantations I've > tried have worked for a m2m relationship however. Any advice is much > appreciated. should be easy enough to create those joins automatically using the relationship: query(School.id, func.count(Coordinator.id)).join(School.coordinators).group_by(School.id).having(func.count(Coordinator.id) > 1) or you could join() explicitly with a separate target/ON clause, shouldn't be necessary though. -- You received this message because you are subscribed to the Google Groups "sqlalchemy" group. To unsubscribe from this group and stop receiving emails from it, send an email to sqlalchemy+unsubscr...@googlegroups.com. To post to this group, send email to sqlalchemy@googlegroups.com. Visit this group at http://groups.google.com/group/sqlalchemy?hl=en. For more options, visit https://groups.google.com/groups/opt_out.
