Hi Michael, Thank you very much for your help and quick response.
The workaround worked. I really like the simplicity of the query api that i automate the generation of it. I will try to incorporate the workaround. Thanks again On Thursday, April 25, 2013 7:31:49 AM UTC+10, Michael Bayer wrote: > > Here's a technique you should be able to use as a workaround: > > 1. for every mapper that you're joining *to* which is also a joined > inheritance subclass, transform it into an aliased() construct > 2. any join involving an aliased() construct, construct the ON criterion > manually. > > These two techniques should bypass all the automation in query.join() > that's failing, such as: > > from sqlalchemy.orm import aliased > > up = aliased(UserPerson) > pa = aliased(PersonAddress) > > session.query(User).\ > outerjoin(up, up.ItemUserPerson_Id == User.Id).\ > outerjoin(pa, pa.ItemPerson_Id == up.Id).\ > outerjoin(pa.Emails).\ > outerjoin(pa.Phones).\ > first() > > > > > On Apr 24, 2013, at 1:38 PM, Michael Bayer > <mik...@zzzcomputing.com<javascript:>> > wrote: > > oh. this *fails in 0.7 also*. I thought this was a regression. Yeah, > this query is a little crazier than we've planned for, I can see the > general thing it's failing to do but will have to see what's involved to > get it going. But not a regression is good news at least. > > > On Apr 24, 2013, at 8:35 AM, gvv <gvve...@gmail.com <javascript:>> wrote: > > Hi All, > > using 7.10 but falls over also in 8.0. > > User has a One2One UserPerson. > UserPerson inherits from Person. > Person has a One2Many PersonAddress. > PersonAddress inherits from Address. > Address has a One2Many Phone and One2Many Email. > > The following query falls over with an (OperationalError) no such column: > Address.Id. > > session.query(User, UserPerson, PersonAddress).filter(User.Id == 1).\ > > outerjoin(User.Personal,UserPerson.Addresses,PersonAddress.Phones,PersonAddress.Emails).first() > > What am I doing wrong ? > > Thanks in advance for your help. > > > sqlalchemy.exc.OperationalError: (OperationalError) no such column: > Address.Id u'SELECT "User"."Id" AS "User_Id", anon_1."UserPerson_Id" AS > "anon_1_UserPerson_Id", anon_1."Person_Id" AS "anon_1_Person_Id", > anon_1."Person_PersonType" AS "anon_1_Person_PersonType", > anon_1."UserPerson_ItemUserPerson_Id" AS > "anon_1_UserPerson_ItemUserPerson_Id", anon_2."PersonAddress_Id" AS > "anon_2_PersonAddress_Id", anon_2."Address_Id" AS "anon_2_Address_Id", > anon_2."Address_AddressType" AS "anon_2_Address_AddressType", > anon_2."PersonAddress_ItemPerson_Id" AS > "anon_2_PersonAddress_ItemPerson_Id" \nFROM "User" LEFT OUTER JOIN (SELECT > "Person"."Id" AS "Person_Id", "Person"."PersonType" AS "Person_PersonType", > "UserPerson"."Id" AS "UserPerson_Id", "UserPerson"."ItemUserPerson_Id" AS > "UserPerson_ItemUserPerson_Id" \nFROM "Person" JOIN "UserPerson" ON > "UserPerson"."Id" = "Person"."Id") AS anon_1 ON > anon_1."UserPerson_ItemUserPerson_Id" = "User"."Id" LEFT OUTER JOIN (SELECT > "Address"."Id" AS "Address_Id", "Address"."AddressType" AS > "Address_AddressType", "PersonAddress"."Id" AS "PersonAddress_Id", > "PersonAddress"."ItemPerson_Id" AS "PersonAddress_ItemPerson_Id" \nFROM > "Address" JOIN "PersonAddress" ON "PersonAddress"."Id" = "Address"."Id") AS > anon_2 ON anon_1."Person_Id" = anon_2."PersonAddress_ItemPerson_Id" LEFT > OUTER JOIN "Phone" ON anon_2."Address_Id" = "Phone"."ItemPhone_Id" LEFT > OUTER JOIN "Email" ON "Address"."Id" = "Email"."ItemEmail_Id" \nWHERE > "User"."Id" = ?\n LIMIT ? OFFSET ?' (1, 1, 0) > > > > -- > You received this message because you are subscribed to the Google Groups > "sqlalchemy" group. > To unsubscribe from this group and stop receiving emails from it, send an > email to sqlalchemy+...@googlegroups.com <javascript:>. > To post to this group, send email to sqlal...@googlegroups.com<javascript:> > . > Visit this group at http://groups.google.com/group/sqlalchemy?hl=en. > For more options, visit https://groups.google.com/groups/opt_out. > > > <test.py><decl_enum.py> > > > > -- > You received this message because you are subscribed to the Google Groups > "sqlalchemy" group. > To unsubscribe from this group and stop receiving emails from it, send an > email to sqlalchemy+...@googlegroups.com <javascript:>. > To post to this group, send email to sqlal...@googlegroups.com<javascript:> > . > Visit this group at http://groups.google.com/group/sqlalchemy?hl=en. > For more options, visit https://groups.google.com/groups/opt_out. > > > > > -- You received this message because you are subscribed to the Google Groups "sqlalchemy" group. To unsubscribe from this group and stop receiving emails from it, send an email to sqlalchemy+unsubscr...@googlegroups.com. To post to this group, send email to sqlalchemy@googlegroups.com. Visit this group at http://groups.google.com/group/sqlalchemy?hl=en. For more options, visit https://groups.google.com/groups/opt_out.
