On Apr 25, 2013, at 4:31 PM, Joril <jor...@gmail.com> wrote: > Hi everyone! > I have this working query: > > select * > from A join B on A.id = B.a_id > where exists (select 1 from C where A.id = C.a_id and C.value > B.value) > > and I tried to implement it like this: > > q = Session.query(entities.A) > q = q.join((entities.B, entities.A.id == entities.B.a_id)) > q = q.filter(entities.A.list_of_Cs.any(entities.C.value > entities.B.value) > > but the generated SQL looks like: > > SELECT [...fields...] > FROM a JOIN b ON a.id = b.a_id > WHERE EXISTS (SELECT 1 > FROM C, B > WHERE A.id = C.a_id AND C.value > B.value) > > As you can see, the inner select doesn't get B.value from the main query as > in my original one, instead it introduces a new join between C and B... > I tried replacing entities.B like this: > b_alias = entities.B.__table__.alias() > but I still get a join inside the subquery... What am I missing?
this will work out of the box in 0.8 as auto-correlation has been improved a lot. in 0.7 you can add correlate() explicitly: from sqlalchemy import * from sqlalchemy.orm import * from sqlalchemy.ext.declarative import declarative_base Base = declarative_base() class A(Base): __tablename__ = 'a' id = Column(Integer, primary_key=True) cs = relationship("C") class B(Base): __tablename__ = 'b' id = Column(Integer, primary_key=True) a_id = Column(Integer, ForeignKey('a.id')) value = Column(Integer) class C(Base): __tablename__ = 'c' id = Column(Integer, primary_key=True) a_id = Column(Integer, ForeignKey('a.id')) value = Column(Integer) e = create_engine("sqlite://", echo=True) sess = Session(e) # in 0.8 q = sess.query(A).join(B, A.id == B.a_id).filter( A.cs.any(C.value > B.value) ) print q # in 0.7 or 0.8 q = sess.query(A).join(B, A.id == B.a_id).filter( A.cs.any(C.value > B.value).correlate(B.__table__) ) print q > > Many thanks! > (SQLAlchemy 0.7.9) > > -- > You received this message because you are subscribed to the Google Groups > "sqlalchemy" group. > To unsubscribe from this group and stop receiving emails from it, send an > email to sqlalchemy+unsubscr...@googlegroups.com. > To post to this group, send email to sqlalchemy@googlegroups.com. > Visit this group at http://groups.google.com/group/sqlalchemy?hl=en. > For more options, visit https://groups.google.com/groups/opt_out. > > -- You received this message because you are subscribed to the Google Groups "sqlalchemy" group. To unsubscribe from this group and stop receiving emails from it, send an email to sqlalchemy+unsubscr...@googlegroups.com. To post to this group, send email to sqlalchemy@googlegroups.com. Visit this group at http://groups.google.com/group/sqlalchemy?hl=en. For more options, visit https://groups.google.com/groups/opt_out.