its a mapper arg called inherit_condition: __mapper_args__ = {"inherit_condition": id==A.id}
On Jul 24, 2013, at 3:42 PM, Seth P <spadow...@gmail.com> wrote: > The code below produces the error message below. How do I tell SQLAlchemy > that the inheritance join condition should be b.id == a.id rather than > b.parent_a_id == a.id? (I would think the primary_key=True could be a > hint...) I can't figure it out from the documentation. > > class A(Base): > __tablename__ = 'a' > id = Column(Integer, primary_key=True) > > class B(A): > __tablename__ = 'b' > id = Column(Integer, ForeignKey('a.id'), primary_key=True) > parent_a_id = Column(Integer, ForeignKey('a.id')) > > sqlalchemy.exc.AmbiguousForeignKeysError: Can't determine join between 'a' > and 'b'; tables have more than one foreign key constraint relationship > between them. Please specify the 'onclause' of this join explicitly. > > > Thanks, > > Seth > > > > -- > You received this message because you are subscribed to the Google Groups > "sqlalchemy" group. > To unsubscribe from this group and stop receiving emails from it, send an > email to sqlalchemy+unsubscr...@googlegroups.com. > To post to this group, send email to sqlalchemy@googlegroups.com. > Visit this group at http://groups.google.com/group/sqlalchemy. > For more options, visit https://groups.google.com/groups/opt_out. > > -- You received this message because you are subscribed to the Google Groups "sqlalchemy" group. To unsubscribe from this group and stop receiving emails from it, send an email to sqlalchemy+unsubscr...@googlegroups.com. To post to this group, send email to sqlalchemy@googlegroups.com. Visit this group at http://groups.google.com/group/sqlalchemy. For more options, visit https://groups.google.com/groups/opt_out.