Hello.
On 20.3.2014 12:13, Richard Gerd Kuesters wrote: > thanks again, AM. no need to have this "extra trouble", as I just asking this > as > a matter of curiosity. it thought it was something rather simple as hell :) I think the following: q = session.query(A, B).filter(A.b_id == B.id) print q # for eachA, eachB in q... should produce what you want: SELECT A.*, B.* FROM A, B WHERE A.b_id = B.id HTH, Ladislav Lenart -- You received this message because you are subscribed to the Google Groups "sqlalchemy" group. To unsubscribe from this group and stop receiving emails from it, send an email to sqlalchemy+unsubscr...@googlegroups.com. To post to this group, send email to sqlalchemy@googlegroups.com. Visit this group at http://groups.google.com/group/sqlalchemy. For more options, visit https://groups.google.com/d/optout.
