Hi, See ColumnElement docs:
http://docs.sqlalchemy.org/en/rel_0_9/core/sqlelement.html#sqlalchemy.sql.expression.ColumnElement ... for your specific example you can call .like(...) on column clauses: >>> print Column('foo', Text).like('bar%baz') foo LIKE :foo_1 More generally, if you wanted some operator other than LIKE, existing in your DB dialect but not yet in SQLAlchemy, then you can use .op(...): >>> print Column('foo', Text).op('FNORD')('foo%') foo FNORD :foo_1 Cheers, Gulli On Thu, Apr 10, 2014 at 12:19 PM, Mark Bird <mark.a.b...@gmail.com> wrote: > I can't seem to find a way to do this without passing raw SQL to .filter() > > I could just do: > > .filter(column == func.substring('string', 1, func.char_length(column))) > > but is it possible to do it with LIKE? > > I.e. I need to return all rows that match the beginning of a string, so > for 'string' I could match 's', 'st', 'str', etc. > > Thanks, > > Mark. > > > -- > You received this message because you are subscribed to the Google Groups > "sqlalchemy" group. > To unsubscribe from this group and stop receiving emails from it, send an > email to sqlalchemy+unsubscr...@googlegroups.com. > To post to this group, send email to sqlalchemy@googlegroups.com. > Visit this group at http://groups.google.com/group/sqlalchemy. > For more options, visit https://groups.google.com/d/optout. > -- You received this message because you are subscribed to the Google Groups "sqlalchemy" group. To unsubscribe from this group and stop receiving emails from it, send an email to sqlalchemy+unsubscr...@googlegroups.com. To post to this group, send email to sqlalchemy@googlegroups.com. Visit this group at http://groups.google.com/group/sqlalchemy. For more options, visit https://groups.google.com/d/optout.
