[sqlalchemy] Re: Dynamically constructing joins

[Jonathan Vanasco]

any reason why you're not building a query like this?

   query = db.session.query(label('sid',
                                     distinct(a[1].c.patient_sid)))
   if n >= 2
      query = query.\
            join(a[2],a[2].c.patient_sid==a[1].c.patient_sid)
   if n >= 3
      query = query.\
            join(a[3],a[3].c.patient_sid==a[1].c.patient_sid)

or

   query = db.session.query(label('sid',
                                     distinct(a[1].c.patient_sid)))
   for i in range(2, n):
      query = query.\
            join(a[i],a[i].c.patient_sid==a[1].c.patient_sid)


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