On 4/27/15 1:52 PM, Adrian wrote:
That's the first thing I've tried. Unfortunately it doesn't work...
---> 1
User.find_all(User.all_emails.any(UserEmail.email.like('%adrian%')))
wait, what is UserEmail, that's the association. This would be the
endpoint class.
Can you share all three classes and the important parts of their
mappings please ?
/home/adrian/dev/indico/env/lib/python2.7/site-packages/sqlalchemy/ext/associationproxy.pyc
in any(self, criterion, **kwargs)
367 """
368
--> 369 if self._value_is_scalar:
370 value_expr = getattr(
371 self.target_class,
self.value_attr).has(criterion, **kwargs)
/home/adrian/dev/indico/env/lib/python2.7/site-packages/sqlalchemy/util/langhelpers.pyc
in __get__(self, obj, cls)
723 if obj is None:
724 return self
--> 725 obj.__dict__[self.__name__] = result = self.fget(obj)
726 return result
727
/home/adrian/dev/indico/env/lib/python2.7/site-packages/sqlalchemy/ext/associationproxy.pyc
in _value_is_scalar(self)
231 def _value_is_scalar(self):
232 return not self._get_property().\
--> 233 mapper.get_property(self.value_attr).uselist
234
235 @util.memoized_property
AttributeError: 'ColumnProperty' object has no attribute 'uselist'
My relationship and association proxy are defined like this:
_all_emails = db.relationship(
'UserEmail',
lazy=True,
viewonly=True,
primaryjoin='User.id == UserEmail.user_id',
collection_class=set,
backref=db.backref('user', lazy=False)
)
On Monday, April 27, 2015 at 5:28:49 PM UTC+2, Michael Bayer wrote:
the has() / any() operators can allow this:
User.all_emails.any(Email.email.like('%foo%'))
it will produce an EXISTS subquery expression, which is not as
efficient in SQL as a regular JOIN.
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