That works great, thanks. 

If I understand correctly, the inherit_condition is deduced automatically, 
when there is no other foreign key linking to the super-class...

On Thursday, November 19, 2015 at 12:52:33 PM UTC-8, Michael Bayer wrote:
>
>
>
> the docs are slight here but the format is like that of the 
> relationship, just not a string: 
>
> class Package(Container): 
>     # ... 
>
>     id = Column(ForeignKey('container.id')) 
>
>     # ... 
>
>     __mapper_args__ = {'polymorphic_identity': 'Package', 
> 'inherit_condition': Container.id == id} 
>
> Note the use of "id" as a local variable within the "class" block. 
>
>

-- 
You received this message because you are subscribed to the Google Groups 
"sqlalchemy" group.
To unsubscribe from this group and stop receiving emails from it, send an email 
to sqlalchemy+unsubscr...@googlegroups.com.
To post to this group, send email to sqlalchemy@googlegroups.com.
Visit this group at http://groups.google.com/group/sqlalchemy.
For more options, visit https://groups.google.com/d/optout.

Reply via email to