This question is sparked by some trouble that I am having with deleting model instances. Please see this question: http://stackoverflow.com/questions/35163325/sqlalchemy-circular-dependency-on-delete
I have set up my models like below. I have several kinds of "tests" defined in my database. Each "test" shares certain columns like 'status', 'date', 'who preformed it', etc. Each different test type then defines columns specific to it. class HasID(object): @declared_attr def id(cls): return Column('id', Integer, Sequence('test_id_seq'), primary_key=True) ... class TestParent(HasID, Model) __tablename__ = 'tests' discriminator = Column(String(50)) __mapper_args__ = {'polymorphic_on': discriminator} ... class FooTest(TestParent, Model): __tablename__ = 'footests' __mapper_args__ = {'polymorphic_identity': 'footests'} id = Column(Integer, ForeignKey('tests.id'), primary_key=True) parent_id = Column(Integer, ForeignKey('footests.id')) children = relationship('FooTest', foreign_keys='FooTest.id', lazy='joined', join_depth=2, cascade='save-update, merge, delete, delete-orphan') ... class BarTest(TestParent, Model): __tablename__ = 'bartests' __mapper_args__ = {'polymorphic_identity': 'bartests'} id = Column(Integer, ForeignKey('tests.id'), primary_key=True) ... Now, I am wondering if this is a correct way to set up the FooTest, as one instance of FooTest may have several child instances of FooTest as children. I am unable to delete any test instance (BarTest or otherwise) and am getting a circular dependency error referring to the FooTest table. Am I missing any fundamental concepts related to table inheritance? Thanks everyone, Brian Leach -- You received this message because you are subscribed to the Google Groups "sqlalchemy" group. To unsubscribe from this group and stop receiving emails from it, send an email to sqlalchemy+unsubscr...@googlegroups.com. To post to this group, send email to sqlalchemy@googlegroups.com. Visit this group at https://groups.google.com/group/sqlalchemy. For more options, visit https://groups.google.com/d/optout.