Hi thanks for your answer Without filter i did not expect any big difference between query(Keyword) or a hypothetical query(User.keywords) but I was thinking it will be nice to do something like this session. query(User.keywords).filter(User ==4) without joins..
My goal was to have a simple query that return a structure like the following with user and user.keywords from sqlalchemy import func myquery = session.query(UserKeyword.user_id, func.array_agg(UserKeyword.keyword_id)).group_by(UserKeyword.user_id).all() myquery result [(4, [3, 4]), (3, [1, 2])] I was thinking associationproxy could help to simplify the ORM statement but it seems I have to join Regards g Am Montag, 22. Februar 2016 12:51:55 UTC+1 schrieb gio: > > Hi > I was trying to use the associationproxy feature like explained > in the basic example > http://docs.sqlalchemy.org/en/latest/orm/extensions/associationproxy.html > Now my question is: > Is it possible to do a query like and have as result an array of array of > keywords? > > session.query(User.keywords) > > Regards > g > > > > > -- You received this message because you are subscribed to the Google Groups "sqlalchemy" group. To unsubscribe from this group and stop receiving emails from it, send an email to sqlalchemy+unsubscr...@googlegroups.com. To post to this group, send email to sqlalchemy@googlegroups.com. Visit this group at https://groups.google.com/group/sqlalchemy. For more options, visit https://groups.google.com/d/optout.
