On 05/10/2016 04:14 PM, Brian Cherinka wrote:
Ok, thanks for the response. What's the timeframe for the 1.1 release?
it will be....this year :) hopefully before the summer is over. I
try to get one major version each year, and I'm pretty busy as this is
the first full year in a long time I'm employed full time. 1.1 is
mostly ready for betas and I just need to find the time to close out a
few more things and put some out.
In the meantime, I will have a look into adding my own class_
attribute, or using the Comparator.
I tried something like
setattr(datadb.Cube.plateifu, "class_", datadb.Cube.id.class_)
but it didn't seem to work. But I'll dig a bit deeper. If I can't get
something working with a 1.0X release, I'll try the 1.1 in bitbucket.
On Tuesday, May 10, 2016 at 2:32:22 PM UTC-4, Mike Bayer wrote:
in 1.1 these hybrids will have the class_ attribute like other
attributes.
Until then you can probably add your own class_ attribute to the object
which you are returning. Also, using a custom Comparator class (see
the example in the hybrid docs) will also return an instrumented
attribute that should have a class_ attribute.
Or you could try using the 1.1 hybrid_property class yourself, it
should
be compatible with 1.0. The commits are illustrated in
https://bitbucket.org/zzzeek/sqlalchemy/issues/3653
<https://bitbucket.org/zzzeek/sqlalchemy/issues/3653> but you can
probably
just use the hybrid.py straight from the git repository with 1.0.
On 05/10/2016 02:01 PM, Brian Cherinka wrote:
>
> I'm trying to build a query system where given a filter parameter
name,
> I can figure out which DeclarativeBase class it is attached to.
I need
> to do this for a mix of standard InstrumentedAttributes and Hybrid
> Properties/Expressions. I have several Declarative Base classes with
> hybrid properties / expressions defined, in addition to the standard
> InstrumentedAttributes from the actual table.
> mydb.dataModelClasses.Cube for example.
>
> For a standard attribute, I can access the class using the class_
variable.
>
> Standard Attribute on the DeclarativeBase class Cube
> |
> type(datadb.Cube.id <http://datadb.Cube.id>)
> sqlalchemy.orm.attributes.InstrumentedAttribute
>
> printdatadb.Cube.id.class_
> mydb.DataModelClasses.Cube
> |
>
> What's the best way to retrieve this same information for a hybrid
> expression? My expressions are other types, thus don't have the
class_
> attribute. One example of my hybrid property defined in the Cube
class
>
> |
> @hybrid_property
> defplateifu(self):
> return'{0}-{1}'.format(self.plate,self.ifu.name
<http://self.ifu.name>)
>
> @plateifu.expression
> defplateifu(cls):
> returnfunc.concat(Cube.plate,'-',IFUDesign.name)
> |
>
> |
> type(datadb.Cube.plateifu)
> sqlalchemy.sql.functions.concat
> |
>
> Since this property is now a function concat, what's the best way to
> retrieve the name of the class that this property is attached to,
namely
> 'mydb.DataModelClasses.Cube'? It doesn't seem to have a .class_ or
> .parent attribute. Is there a way to add a new attribute onto my
hybrid
> columns that let me access the parent class?
>
> I need to do this for a variety of hybrid properties/expressions,
that
> are all constructed in unique ways. This particular example is a
> function concat, however I have others that are of type
> sqlalchemy.sql.elements.BinaryExpression.
>
> Is there a way to generically do this no matter the type of hybrid
> expression I define?
>
> Thanks.
>
> --
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