you'd say:
session.expire(model, ["items"])
On 10/27/2016 04:47 PM, Colton Allen wrote:
Sorry I must have combined multiple attempts into one example. When you
say expire the relationship, what do you mean?
On Thursday, October 27, 2016 at 4:30:36 PM UTC-4, Mike Bayer wrote:
Hello -
I've rebuilt your fragment into a full example in order to determine
what the behavior is here, as make_transient() has no defined behavior
for loaded relationships.
Your error does not reproduce with your code fragment as given, because
you are setting the list of items to itself, and this means there is no
history at all; the unit of work will ignore it.
Setting the list to a series of three brand new secondary items
produces
the error you see because this generates deletion events for the
existing objects which fail because the state of the object is
transient.
The solution is to expire the relationship attribute first so that
it is
reset for the transient state.
On 10/27/2016 03:43 PM, Colton Allen wrote:
> I want to create a new row with all of the same data. However,
(using
> make_transient) the many-to-many "items" relationship doesn't
carry over
> to the new model. When I manually set the items I recieve a
> "StaleDataError". How can I insert the many-to-many relationships so
> this does not happen?
> *
> *
> *
> My code:*
>
> class Test(Model):
> id = Column(Integer, primary_key=True)
> items = orm.relationship('ItemModel', secondary=test_item_table)
>
>
> model = Test.query.first()
> list_of_items = model.items.copy()
>
> make_transient(model)
> model.id <http://model.id> = None
> model.items = list_of_items
>
> session.add(model)
> session.commit()
>
> # sqlalchemy.orm.exc.StaleDataError: DELETE statement on table
> 'test_item' expected to delete 1 row(s); Only 0 were matched.
>
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