On Thu, Nov 10, 2016 at 9:32 AM, Dorian Hoxha <dorian.ho...@gmail.com> wrote: > So I have: > > class Thing(): > current_user_like = relationship(Like) > > class User(): > pass > > class Like(): > user_id = Column(primary_key=True) > thing_id = Column(primary_key=True) > > > Now I want, to do "session.query(Thing).all()" and also join the > "current_user_like" for each Thing, but only get 1 row instead of the whole > collection of `likes` for each Thing. > I know this can be done with db.session.query(Thing,Like) and doing an > outerjoin, but can it be done so I get Like embedded inside > Thing.current_user_like ?
I'm not sure I understand the question. How do you specify which user_id should correspond to the "current user"? Are you asking how to create the "current_user_like" relationship, or how to populate it during a query? In general, if you want a relationship to be populated during a query, you use one of the loader options such as joinedload or subqueryload: http://docs.sqlalchemy.org/en/latest/orm/loading_relationships.html#using-loader-strategies-lazy-loading-eager-loading Simon -- SQLAlchemy - The Python SQL Toolkit and Object Relational Mapper http://www.sqlalchemy.org/ To post example code, please provide an MCVE: Minimal, Complete, and Verifiable Example. See http://stackoverflow.com/help/mcve for a full description. --- You received this message because you are subscribed to the Google Groups "sqlalchemy" group. To unsubscribe from this group and stop receiving emails from it, send an email to sqlalchemy+unsubscr...@googlegroups.com. To post to this group, send email to sqlalchemy@googlegroups.com. Visit this group at https://groups.google.com/group/sqlalchemy. For more options, visit https://groups.google.com/d/optout.
