Hi!
I don't even quote my old message since it's just confusing.
In my head the question made sense ;)
So I try again with a code example:
I have a class `User`:
#+BEGIN_SRC python
class User(Base):
id = Column(Integer, primary_key=True)
name = Column(String(64))
email = Column(String(64))
languages = relationship('Language', secondary='user_languages')
#+END_SRC
I already have a lot of users stored in my DB.
And I know that I have, for example, this user in my DB:
#+BEGIN_SRC python
user_dict = {
'id': 23,
'name': 'foo',
'email': 'foo@bar',
}
#+END_SRC
So I have all the attributes but the relations.
Now I want to make a sqlalchemy `User` instance
and kind of register it in sqlalchemy's system
so I can get the `languages` if needed.
#+BEGIN_SRC python
user = User(**user_dict)
# Now I can access the id, name email attributes
assert user.id == 23
# but since sqlalchemy thinks it's a new model it doesn't
# lazy load any relationships
assert len(user.languages) == 0
# I want here that the languages for the user with id 23 appear
# So I want that `user` is the same as when I would have done
user_from_db = DBSession.query(User).get(23)
assert user == user_from_db
#+END_SRC
The use-case is that I have a big model with lots of complex
relationships but 90% of the time I don't need the data from those.
So I only want to cache the direct attributes plus what else I need
and then load those from the cache like above and be able to
use the sqlalchemy model like I would have queried it from the db.
Hope it makes a bit more sense now.
Sorry for the confusing first question and wasting your time.
Thanks,
Daniel
--
SQLAlchemy -
The Python SQL Toolkit and Object Relational Mapper
http://www.sqlalchemy.org/
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