On Fri, May 4, 2018 at 9:49 PM, Dave von Umlaut <zedrd...@gmail.com> wrote:
> Also… Not sure if that's related, but I also seem unable to implement > is_latest_version with a nicer join-based query (I suspect solving my Alias > issues might help): > … FROM child c1 JOIN child c2 ON c2.id = c1.id AND c2.version > c1.version > WHERE c2.id IS NULL you can of course write that query using query.join() directly but the column_property() can't change the query to have a JOIN in the FROM clause automatically. persisting the is_current_version value might be overall easier. > > > Thanks in advance for any help! > -- > Dave > > -- > SQLAlchemy - > The Python SQL Toolkit and Object Relational Mapper > > http://www.sqlalchemy.org/ > > To post example code, please provide an MCVE: Minimal, Complete, and > Verifiable Example. See http://stackoverflow.com/help/mcve for a full > description. > --- > You received this message because you are subscribed to the Google Groups > "sqlalchemy" group. > To unsubscribe from this group and stop receiving emails from it, send an > email to sqlalchemy+unsubscr...@googlegroups.com. > To post to this group, send email to sqlalchemy@googlegroups.com. > Visit this group at https://groups.google.com/group/sqlalchemy. > For more options, visit https://groups.google.com/d/optout. -- SQLAlchemy - The Python SQL Toolkit and Object Relational Mapper http://www.sqlalchemy.org/ To post example code, please provide an MCVE: Minimal, Complete, and Verifiable Example. See http://stackoverflow.com/help/mcve for a full description. --- You received this message because you are subscribed to the Google Groups "sqlalchemy" group. To unsubscribe from this group and stop receiving emails from it, send an email to sqlalchemy+unsubscr...@googlegroups.com. To post to this group, send email to sqlalchemy@googlegroups.com. Visit this group at https://groups.google.com/group/sqlalchemy. For more options, visit https://groups.google.com/d/optout.