I have an ORM setup with a "departments_milestones" table ("dm",
DepartmentMilestone objects), with "department_id" and "seqOrder" Fields.
Each department has a few records in this table, ordered within the
department by "seqOrder" (so seqOrder is not unique).
Another object "ShotsStatus" contains a collection of these
DepartmentMilestone objects, one for each department. I'm interested in
getting the ShotsStatus records that are at the "last" milestone in its
department - the one with the highest "seqOrder" value for the department.
In SQL I can do something like this, with a subquery to select the
departmental milestone records, reverse sort them so the 'last' one is
first, and LIMIT 1 to get it, which is compared to the outer record.
select * FROM shots_status ss
left outer join otherschema.departments_milestones dm on
(dm.department_id=ss.dept_id AND dm.milestone_id = ss.status_id)
where ss.dept_id=723
and dm.id = (SELECT dmsq.id FROM plumber.departments_milestones dmsq WHERE
dmsq.department_id=dm.department_id ORDER BY dmsq.seqOrder DESC LIMIT 1)
I'd like to create a hybrid property "isLast" on the DepartmentMilestone
object that returns True if it represents the 'last' milestone. I'm
having trouble figuring out what sort of sqlalchemy select coding I'd need
to recreate the subquery from the SQL code to do this.
--
SQLAlchemy -
The Python SQL Toolkit and Object Relational Mapper
http://www.sqlalchemy.org/
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