Not just for warning. Also this raise load issue. yes, i see that I can't mark none. If I could though, that would be awesome since I think it would solve this problem? I can test by setting one foreign and seeing if that works.
On Wednesday, October 10, 2018 at 1:13:32 PM UTC-4, Mike Bayer wrote: > > On Wed, Oct 10, 2018 at 12:56 PM Alex Rothberg <agrot...@gmail.com > <javascript:>> wrote: > > > > let me get that. in the meantime, what are your thoughts on just > removing the view only from the original relationship and then using an > explicit primary join where none of the columns are marked foreign? > Theoretically that should solve this problem, no? > > is this just for the warning? I don't think the relationship() can > be set up with no columns marked as foreign, it takes that as a cue > that it should figure out the "foreign" columns on its own. > > There's another way to make sure Employee is always dependent on > FundTitle but it's a little bit off-label. Add the dependency you > want directly into the unit of work: > > from sqlalchemy.orm import unitofwork > from sqlalchemy import event > > > @event.listens_for(Session, "before_flush") > def _add_dep(session, context, objects): > context.dependencies.update([ > ( > unitofwork.SaveUpdateAll(context, inspect(FundTitle)), > unitofwork.SaveUpdateAll(context, inspect(Employee)) > ) > ]) > > > > > > > > > On Wednesday, October 10, 2018 at 12:41:25 PM UTC-4, Alex Rothberg > wrote: > >> > >> Is it possible to specific a non viewonly relationship in which I have > a primary join specified in which none of the fk's are marked "foreign"? ie > where I can mark the relationship dependancy but it wont set any columns? > It looks like there may be some logic in sqla that assume all columns are > fk if none are specified as foreign? > >> > >> On Wednesday, October 10, 2018 at 11:56:49 AM UTC-4, Alex Rothberg > wrote: > >>> > >>> So one minor issue and one big issue with that solution: > >>> 1. minor issue, I now get these: SAWarning: relationship 'XXXX' will > copy columnYYYY to column ZZZZ, which conflicts with relationship(s): '.... > >>> 2. major issue, I use raiseload("*") and now I start seeing: > sqlalchemy.exc.InvalidRequestError: 'Employee._ft_for_dependency' is not > available due to lazy='raise' > >>> > >>> On Wednesday, October 10, 2018 at 9:57:55 AM UTC-4, Mike Bayer wrote: > >>>> > >>>> On Tue, Oct 9, 2018 at 6:45 PM Alex Rothberg <agrot...@gmail.com> > wrote: > >>>> > > >>>> > Okay with some small tweaks to your original code, I am able to > show the issue I am having. comment out flush to see issue: > >>>> > >>>> so what you're doing here is making Employee dependent on FundTitle, > >>>> which makes this a little out of the ordinary but this is fine. You > >>>> need to give the ORM a clue that this dependency exists, since it > >>>> never looks at foreign key constraints unless you tell it to. > >>>> Adding a relationship to FundTitle that doesn't have viewonly=True is > >>>> an easy way to do this, there's no need to ever make use of the > >>>> relationship otherwise: > >>>> > >>>> class Employee(Base): > >>>> __tablename__ = 'employee' > >>>> > >>>> # ... > >>>> fund_title = relationship(FundTitle, viewonly=True) > >>>> > >>>> _ft_for_dependency = relationship(FundTitle) > >>>> > >>>> __table_args__ = ( > >>>> ForeignKeyConstraint( > >>>> (title_id, department_id, fund_id), > >>>> (FundTitle.title_id, FundTitle.department_id, > FundTitle.fund_id) > >>>> ), > >>>> ) > >>>> > >>>> then you can take the flush() out and there's no issue, as long as > >>>> you're always making sure that FundTitle object is present either in > >>>> the current Session or the row in the database exists. > >>>> > >>>> > >>>> > > >>>> > from sqlalchemy import * > >>>> > from sqlalchemy.orm import * > >>>> > from sqlalchemy.ext.declarative import declarative_base > >>>> > > >>>> > Base = declarative_base() > >>>> > > >>>> > > >>>> > class Title(Base): > >>>> > __tablename__ = 'title' > >>>> > id = Column(Integer, primary_key=True) > >>>> > department_id = Column(ForeignKey('department.id'), > nullable=False) > >>>> > > >>>> > department = relationship(lambda: Department) > >>>> > > >>>> > > >>>> > class Department(Base): > >>>> > __tablename__ = 'department' > >>>> > id = Column(Integer, primary_key=True) > >>>> > > >>>> > > >>>> > class Fund(Base): > >>>> > __tablename__ = 'fund' > >>>> > id = Column(Integer, primary_key=True) > >>>> > title_id = Column(ForeignKey('title.id'), nullable=False) > >>>> > department_id = Column(ForeignKey('department.id'), > nullable=False) > >>>> > department = relationship("Department") > >>>> > title = relationship("Title") > >>>> > > >>>> > > >>>> > class FundTitle(Base): > >>>> > __tablename__ = 'fund_title' > >>>> > id = Column(Integer, primary_key=True) > >>>> > title_id = Column(ForeignKey('title.id'), nullable=False) > >>>> > department_id = Column(ForeignKey('department.id'), > nullable=False) > >>>> > fund_id = Column(ForeignKey('fund.id'), nullable=False) > >>>> > department = relationship("Department") > >>>> > title = relationship("Title") > >>>> > fund = relationship("Fund") > >>>> > > >>>> > __table_args__ = ( > >>>> > UniqueConstraint( > >>>> > title_id, department_id, fund_id > >>>> > ), > >>>> > ) > >>>> > > >>>> > > >>>> > class Employee(Base): > >>>> > __tablename__ = 'employee' > >>>> > id = Column(Integer, primary_key=True) > >>>> > title_id = Column(ForeignKey('title.id'), nullable=False) > >>>> > department_id = Column(ForeignKey('department.id'), > nullable=False) > >>>> > fund_id = Column(ForeignKey('fund.id'), nullable=False) > >>>> > > >>>> > department = relationship(lambda: Department) > >>>> > title = relationship("Title") > >>>> > fund = relationship("Fund") > >>>> > > >>>> > fund_title = relationship(FundTitle, viewonly=True) > >>>> > > >>>> > > >>>> > __table_args__ = ( > >>>> > ForeignKeyConstraint( > >>>> > (title_id, department_id, fund_id), > (FundTitle.title_id, FundTitle.department_id, FundTitle.fund_id) > >>>> > ), > >>>> > ) > >>>> > > >>>> > > >>>> > e = create_engine("postgresql://localhost/test_issue", echo=False) > >>>> > > >>>> > # Base.metadata.drop_all(e) > >>>> > Base.metadata.create_all(e) > >>>> > > >>>> > s = Session(e) > >>>> > # s.rollback() > >>>> > > >>>> > while True: > >>>> > d1 = Department() > >>>> > t1 = Title(department=d1) > >>>> > f1 = Fund(department=d1, title=t1) > >>>> > ft1 = FundTitle(title=t1, department=d1, fund=f1) > >>>> > > >>>> > s.add_all([d1, t1, f1, ft1]) > >>>> > > >>>> > s.flush() > >>>> > > >>>> > e1 = Employee(title=t1, department=d1, fund=f1) > >>>> > > >>>> > s.add_all([e1,]) > >>>> > s.commit() > >>>> > > >>>> > On Tuesday, October 9, 2018 at 12:20:30 PM UTC-4, Mike Bayer wrote: > >>>> >> > >>>> >> On Tue, Oct 9, 2018 at 10:44 AM Alex Rothberg <agrot...@gmail.com> > wrote: > >>>> >> > > >>>> >> > In looking at what you wrote doesn't this cause an fk violation > (it does for me): > >>>> >> > 2018-10-08 10:18:38,760 INFO sqlalchemy.engine.base.Engine > INSERT INTO employee (title_id, department_id, fund_id) VALUES > (%(title_id)s, %(department_id)s, %(fund_id)s) RETURNING employee.id > >>>> >> > 2018-10-08 10:18:38,763 INFO sqlalchemy.engine.base.Engine > INSERT INTO fund_title (title_id, department_id, fund_id) VALUES > (%(title_id)s, %(department_id)s, %(fund_id)s) RETURNING fund_title.id > >>>> >> > > >>>> >> > in that a a (non deferred) fk is violated between employee and > fund_title ? > >>>> >> > >>>> >> see we need to see how youve laid out your ForeignKeyConstraints, > if > >>>> >> they are composite and overlapping, there are additional options > that > >>>> >> may be needed (specifically the post_update flag). you'll note I > laid > >>>> >> out all FKs as single column. > >>>> >> > >>>> >> > > >>>> >> > On Mon, Oct 8, 2018 at 10:20 AM Mike Bayer < > mik...@zzzcomputing.com> wrote: > >>>> >> >> > >>>> >> >> On Sun, Oct 7, 2018 at 7:11 PM Alex Rothberg < > agrot...@gmail.com> wrote: > >>>> >> >> > > >>>> >> >> > Okay so I investigated / thought about this further. The > issue is that while I do have a relationship between the various models, > some of the relationships are viewonly since I have overlapping fks. > >>>> >> >> > > >>>> >> >> > For example I have a model Employee, which has fks: > department_id, title_id, and fund_id. The related models are Department (fk > department_id), Title (fk department_id and title_id) , Fund (fk fund_id) > and FundTitle (fk department_id, title_id and fund_id). I have set > FundTitle to viewonly. When updating / creating an Employee, I do create > and add a new FundTitle to the session, however I don't assign it to the > employee as the relationship is viewonly. If I don't flush before making > the assignment, the final flush / commit attempts to update / create the > employee before creating the FundTitle. > >>>> >> >> > >>>> >> >> let's work with source code that is runnable (e.g. MCVE). > Below is > >>>> >> >> the model that it seems you are describing, and then there's a > >>>> >> >> demonstration of assembly of all those components using > relationships, > >>>> >> >> a single flush and it all goes in in the correct order, all FKs > are > >>>> >> >> nullable=False. > >>>> >> >> > >>>> >> >> from sqlalchemy import * > >>>> >> >> from sqlalchemy.orm import * > >>>> >> >> from sqlalchemy.ext.declarative import declarative_base > >>>> >> >> > >>>> >> >> Base = declarative_base() > >>>> >> >> > >>>> >> >> > >>>> >> >> class Employee(Base): > >>>> >> >> __tablename__ = 'employee' > >>>> >> >> id = Column(Integer, primary_key=True) > >>>> >> >> title_id = Column(ForeignKey('title.id'), nullable=False) > >>>> >> >> department_id = Column(ForeignKey('department.id'), > nullable=False) > >>>> >> >> fund_id = Column(ForeignKey('fund.id'), nullable=False) > >>>> >> >> department = relationship("Department") > >>>> >> >> title = relationship("Title") > >>>> >> >> fund = relationship("Fund") > >>>> >> >> > >>>> >> >> > >>>> >> >> class Title(Base): > >>>> >> >> __tablename__ = 'title' > >>>> >> >> id = Column(Integer, primary_key=True) > >>>> >> >> department_id = Column(ForeignKey('department.id'), > nullable=False) > >>>> >> >> department = relationship("Department") > >>>> >> >> > >>>> >> >> > >>>> >> >> class Department(Base): > >>>> >> >> __tablename__ = 'department' > >>>> >> >> id = Column(Integer, primary_key=True) > >>>> >> >> > >>>> >> >> > >>>> >> >> class Fund(Base): > >>>> >> >> __tablename__ = 'fund' > >>>> >> >> id = Column(Integer, primary_key=True) > >>>> >> >> title_id = Column(ForeignKey('title.id'), nullable=False) > >>>> >> >> department_id = Column(ForeignKey('department.id'), > nullable=False) > >>>> >> >> department = relationship("Department") > >>>> >> >> title = relationship("Title") > >>>> >> >> > >>>> >> >> > >>>> >> >> class FundTitle(Base): > >>>> >> >> __tablename__ = 'fund_title' > >>>> >> >> id = Column(Integer, primary_key=True) > >>>> >> >> title_id = Column(ForeignKey('title.id'), nullable=False) > >>>> >> >> department_id = Column(ForeignKey('department.id'), > nullable=False) > >>>> >> >> fund_id = Column(ForeignKey('fund.id'), nullable=False) > >>>> >> >> department = relationship("Department") > >>>> >> >> title = relationship("Title") > >>>> >> >> fund = relationship("Fund") > >>>> >> >> > >>>> >> >> e = create_engine("postgresql://scott:tiger@localhost/test", > echo=True) > >>>> >> >> Base.metadata.create_all(e) > >>>> >> >> > >>>> >> >> s = Session(e) > >>>> >> >> > >>>> >> >> d1 = Department() > >>>> >> >> t1 = Title(department=d1) > >>>> >> >> f1 = Fund(department=d1, title=t1) > >>>> >> >> ft1 = FundTitle(title=t1, department=d1, fund=f1) > >>>> >> >> e1 = Employee(title=t1, department=d1, fund=f1) > >>>> >> >> > >>>> >> >> s.add_all([d1, t1, f1, ft1, e1]) > >>>> >> >> s.commit() > >>>> >> >> > >>>> >> >> > >>>> >> >> the INSERTs can be ordered naturally here and the unit of work > will do > >>>> >> >> that for you if you use relationship: > >>>> >> >> > >>>> >> >> BEGIN (implicit) > >>>> >> >> 2018-10-08 10:18:38,750 INFO sqlalchemy.engine.base.Engine > INSERT INTO > >>>> >> >> department DEFAULT VALUES RETURNING department.id > >>>> >> >> 2018-10-08 10:18:38,750 INFO sqlalchemy.engine.base.Engine {} > >>>> >> >> 2018-10-08 10:18:38,753 INFO sqlalchemy.engine.base.Engine > INSERT INTO > >>>> >> >> title (department_id) VALUES (%(department_id)s) RETURNING > title.id > >>>> >> >> 2018-10-08 10:18:38,753 INFO sqlalchemy.engine.base.Engine > {'department_id': 1} > >>>> >> >> 2018-10-08 10:18:38,757 INFO sqlalchemy.engine.base.Engine > INSERT INTO > >>>> >> >> fund (title_id, department_id) VALUES (%(title_id)s, > >>>> >> >> %(department_id)s) RETURNING fund.id > >>>> >> >> 2018-10-08 10:18:38,757 INFO sqlalchemy.engine.base.Engine > >>>> >> >> {'title_id': 1, 'department_id': 1} > >>>> >> >> 2018-10-08 10:18:38,760 INFO sqlalchemy.engine.base.Engine > INSERT INTO > >>>> >> >> employee (title_id, department_id, fund_id) VALUES > (%(title_id)s, > >>>> >> >> %(department_id)s, %(fund_id)s) RETURNING employee.id > >>>> >> >> 2018-10-08 10:18:38,761 INFO sqlalchemy.engine.base.Engine > >>>> >> >> {'title_id': 1, 'department_id': 1, 'fund_id': 1} > >>>> >> >> 2018-10-08 10:18:38,763 INFO sqlalchemy.engine.base.Engine > INSERT INTO > >>>> >> >> fund_title (title_id, department_id, fund_id) VALUES > (%(title_id)s, > >>>> >> >> %(department_id)s, %(fund_id)s) RETURNING fund_title.id > >>>> >> >> 2018-10-08 10:18:38,764 INFO sqlalchemy.engine.base.Engine > >>>> >> >> {'title_id': 1, 'department_id': 1, 'fund_id': 1} > >>>> >> >> 2018-10-08 10:18:38,766 INFO sqlalchemy.engine.base.Engine > COMMIT > >>>> >> >> > >>>> >> >> > >>>> >> >> > >>>> >> >> > >>>> >> >> > >>>> >> >> > > >>>> >> >> > On Tuesday, September 18, 2018 at 9:02:30 AM UTC-4, Mike > Bayer wrote: > >>>> >> >> >> > >>>> >> >> >> if there are no dependencies between two particular objects > of > >>>> >> >> >> different classes, say A and B, then there is no > deterministic > >>>> >> >> >> ordering between them. For objects of the same class, they > are > >>>> >> >> >> inserted in the order in which they were added to the > Session. > >>>> >> >> >> > >>>> >> >> >> the correct way to solve this problem in SQLAlchemy is to > use > >>>> >> >> >> relationship() fully. I know you've stated that these > objects have a > >>>> >> >> >> relationship() between them but you have to actually use it, > that is: > >>>> >> >> >> > >>>> >> >> >> obj_a = A() > >>>> >> >> >> obj_b = B() > >>>> >> >> >> > >>>> >> >> >> obj_a.some_relationship = obj_b # will definitely flush > correctly > >>>> >> >> >> unless there is a bug > >>>> >> >> >> > >>>> >> >> >> OTOH if you are only using foreign key attributes, the ORM > does *not* > >>>> >> >> >> have any idea in how it should be flushing these: > >>>> >> >> >> > >>>> >> >> >> obj_a = A() > >>>> >> >> >> obj_b = B() > >>>> >> >> >> > >>>> >> >> >> obj_a.some_fk = obj_b.some_id # ORM doesn't care about > this, no > >>>> >> >> >> ordering is implied > >>>> >> >> >> > >>>> >> >> >> > >>>> >> >> >> since you said you're not setting any IDs, I'm not sure how > you could > >>>> >> >> >> be doing the above. > >>>> >> >> >> > >>>> >> >> >> > >>>> >> >> >> > >>>> >> >> >> > >>>> >> >> >> > >>>> >> >> >> > >>>> >> >> >> On Tue, Sep 18, 2018 at 5:53 AM Simon King < > si...@simonking.org.uk> wrote: > >>>> >> >> >> > > >>>> >> >> >> > It's not something I've ever looked into, but I'm not > aware of any > >>>> >> >> >> > debugging options here, no. You'd probably want to start > by scattering > >>>> >> >> >> > print statements around the UOWTransaction class > >>>> >> >> >> > ( > https://bitbucket.org/zzzeek/sqlalchemy/src/c94d67892e68ac317d72eb202cca427084b3ca74/lib/sqlalchemy/orm/unitofwork.py?at=master&fileviewer=file-view-default#unitofwork.py-111) > > > >>>> >> >> >> > > >>>> >> >> >> > Looking at that code made me wonder whether you've set any > particular > >>>> >> >> >> > cascade options on your relationship; I'm not sure if > cascade options > >>>> >> >> >> > affect the dependency calculation. > >>>> >> >> >> > > >>>> >> >> >> > Simon > >>>> >> >> >> > > >>>> >> >> >> > On Tue, Sep 18, 2018 at 5:28 AM Alex Rothberg < > agrot...@gmail.com> wrote: > >>>> >> >> >> > > > >>>> >> >> >> > > In order to guide me in stripping down this code to > produce an example for positing, are there any options / flags / > introspections I can turn on to understand how sql makes decisions about > the order in which is writes statements to the DB? > >>>> >> >> >> > > > >>>> >> >> >> > > On Friday, September 14, 2018 at 10:13:45 AM UTC-4, > Simon King wrote: > >>>> >> >> >> > >> > >>>> >> >> >> > >> In that case can you show us the code that is causing > the problem? > >>>> >> >> >> > >> On Fri, Sep 14, 2018 at 2:55 PM Alex Rothberg < > agrot...@gmail.com> wrote: > >>>> >> >> >> > >> > > >>>> >> >> >> > >> > I am not generating any IDs myself and I already have > relationships between the models. > >>>> >> >> >> > >> > > >>>> >> >> >> > >> > On Friday, September 14, 2018 at 4:33:08 AM UTC-4, > Simon King wrote: > >>>> >> >> >> > >> >> > >>>> >> >> >> > >> >> On Thu, Sep 13, 2018 at 10:50 PM Alex Rothberg < > agrot...@gmail.com> wrote: > >>>> >> >> >> > >> >> > > >>>> >> >> >> > >> >> > Is it possible to hint at sqla the order in which > it should write out changes to the DB? > >>>> >> >> >> > >> >> > > >>>> >> >> >> > >> >> > I am having issues in which I add two new objects > to a session, a and b where a depends on b, but sqla is flushing a before b > leading to an fk issue. I can solve this a few ways: explicitly calling > flush after adding b, or changing the fk constraint to be initially > deferred. Ideally I would not have to do either of these. > >>>> >> >> >> > >> >> > > >>>> >> >> >> > >> >> > >>>> >> >> >> > >> >> If you have configured a relationship between the > two classes > >>>> >> >> >> > >> >> ( > http://docs.sqlalchemy.org/en/latest/orm/tutorial.html#building-a-relationship), > > > >>>> >> >> >> > >> >> and you've linked the objects together using that > relationship (a.b = > >>>> >> >> >> > >> >> b), then SQLAlchemy will flush them in the correct > order. If you are > >>>> >> >> >> > >> >> generating your IDs in Python and assigning them to > the primary and > >>>> >> >> >> > >> >> foreign key columns directly, SQLAlchemy probably > won't understand the > >>>> >> >> >> > >> >> dependency. > >>>> >> >> >> > >> >> > >>>> >> >> >> > >> >> Does using a relationship fix your problem? > >>>> >> >> >> > >> >> > >>>> >> >> >> > >> >> Simon > >>>> >> >> >> > >> > > >>>> >> >> >> > >> > -- > >>>> >> >> >> > >> > SQLAlchemy - > >>>> >> >> >> > >> > The Python SQL Toolkit and Object Relational Mapper > >>>> >> >> >> > >> > > >>>> >> >> >> > >> > http://www.sqlalchemy.org/ > >>>> >> >> >> > >> > > >>>> >> >> >> > >> > To post example code, please provide an MCVE: > Minimal, Complete, and Verifiable Example. 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