Creating a pandas dataframe that contained descriptive column names formerly was as easy as:
result_set = session.query(cls.column_1) df = pandas.Dataframe(result_set) print df.column_1 but while this works in 1.3.20, in later versions of SA such as 1.4.19, there is not enough column info supplied by SA to form the same symbolic column names. Thus, the above code would fail when attempting to access df.column_1 in SA 1.4.19 but not fail in SA 1.3.20. Anyway to supply a flag to query() to provide the extra column that existed in older SA versions? -- SQLAlchemy - The Python SQL Toolkit and Object Relational Mapper http://www.sqlalchemy.org/ To post example code, please provide an MCVE: Minimal, Complete, and Verifiable Example. See http://stackoverflow.com/help/mcve for a full description. --- You received this message because you are subscribed to the Google Groups "sqlalchemy" group. To unsubscribe from this group and stop receiving emails from it, send an email to sqlalchemy+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/d/msgid/sqlalchemy/2664002d-25cc-450d-bc51-8652a7df3d53n%40googlegroups.com.
