This is very helpful. How to return a list of scalar values in this case? Now the query returns a list of tuples, and each tuple only has one value, which is what actually needed. Is there a parameter to return a series of scalar value like this? On Wednesday, November 10, 2021 at 12:05:27 PM UTC-8 Mike Bayer wrote:
> it has to do with how SQLAlchemy determines the FROM list in a select() > statement. > > if you say select(table.c.id), it knows that "table" is the thing to > select "from". > > however, if you say select(select(...).correlate(...).scalar_subquery()), > that's assuming it's a SELECT from a scalar subquery, which normally does > not imply a FROM clause. > > In this case, that you are saying correlate(C), we could argue that *does* > imply a FROM clause of some kind, but SQLAlchemy doesn't make that leap > right now. You might have said correlate(C, D) or correlate_except(Q) and > then it's not as clear what the scalar subquery would be selected FROM. > > going further, there *could* be some new kind of API where a scalar > subquery could suggest a FROM clause that should be used when this subquery > is selected FROM. that would allow your column_property() to be built up > such that it would be "self sufficient" when queried by itself. but again > we don't have that right now. > > with all those options exhausted, for SQLAlchemy to be given > select(select().scalar_subquery()), and then to produce "SELECT * FROM > (SELECT ....) FROM <some table>", that FROM part has to be added on > explicitly, i.e. select(select().scalar_subuqery()).select_from(<some > table>). > > > > On Wed, Nov 10, 2021, at 2:35 PM, niuji...@gmail.com wrote: > > This works! Could you explain a little about this differences by using > select_from here? I think this is very important and useful, really want to > learn it right. > > On Wednesday, November 10, 2021 at 5:55:44 AM UTC-8 Mike Bayer wrote: > > > try calling: > > query(C.symbol_from_a).select_from(C) > > > > On Wed, Nov 10, 2021, at 4:50 AM, niuji...@gmail.com wrote: > > class A(Base): > primary_id = Column(Integer, prirmary_key=True) > some_A_marker = Column(String) > > class B(Base): > primary_id = Column(Integer, primary_key=True) > referencing_A_id = Column(Integer, ForeignKey(A.primary_id)) > > class C(Base): > primary_id = Column(Integer, primary_key=True) > basedOn_B_id = Column(Integer, ForeignKey(B.primary_id)) > symbol_from_A = column_property( > > sasql.select(A.some_A_marker).select_from(A).join(B).where(B.primary_id == > C.basedOn_B_id).correlate(C).scalar_subquery().label("symbol_from_A") > ) > > > When I query this highlighted column_property along with the whole object, > it works fine: > > >>> sess.query(C, C.symbol_from_A).all() > > However, when I query this column_property alone, it doesn't work: > > >>>sess.query(C.symbol_from_A).distinct().all() > > I noticed that somehow the correlated subquery wasn't executed property > when query that column_property independently. > > How to solve this? > > > -- > SQLAlchemy - > The Python SQL Toolkit and Object Relational Mapper > > http://www.sqlalchemy.org/ > > To post example code, please provide an MCVE: Minimal, Complete, and > Verifiable Example. See http://stackoverflow.com/help/mcve for a full > description. > --- > You received this message because you are subscribed to the Google Groups > "sqlalchemy" group. > To unsubscribe from this group and stop receiving emails from it, send an > email to sqlalchemy+...@googlegroups.com. > To view this discussion on the web visit > https://groups.google.com/d/msgid/sqlalchemy/f7a0c360-ada2-456b-b02a-498ca50334f3n%40googlegroups.com > > <https://groups.google.com/d/msgid/sqlalchemy/f7a0c360-ada2-456b-b02a-498ca50334f3n%40googlegroups.com?utm_medium=email&utm_source=footer> > . > > > -- > SQLAlchemy - > The Python SQL Toolkit and Object Relational Mapper > > http://www.sqlalchemy.org/ > > To post example code, please provide an MCVE: Minimal, Complete, and > Verifiable Example. See http://stackoverflow.com/help/mcve for a full > description. > --- > You received this message because you are subscribed to the Google Groups > "sqlalchemy" group. > To unsubscribe from this group and stop receiving emails from it, send an > email to sqlalchemy+...@googlegroups.com. > > To view this discussion on the web visit > https://groups.google.com/d/msgid/sqlalchemy/8549e3f3-11fb-47e1-b86a-270fecce8caan%40googlegroups.com > > <https://groups.google.com/d/msgid/sqlalchemy/8549e3f3-11fb-47e1-b86a-270fecce8caan%40googlegroups.com?utm_medium=email&utm_source=footer> > . > > > -- SQLAlchemy - The Python SQL Toolkit and Object Relational Mapper http://www.sqlalchemy.org/ To post example code, please provide an MCVE: Minimal, Complete, and Verifiable Example. See http://stackoverflow.com/help/mcve for a full description. --- You received this message because you are subscribed to the Google Groups "sqlalchemy" group. To unsubscribe from this group and stop receiving emails from it, send an email to sqlalchemy+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/d/msgid/sqlalchemy/b2059a01-5c3f-455c-aa3c-44590fe2f166n%40googlegroups.com.