There's no good way to handle graphs in SQL.  If you had a 
tree, you could use Celko's nested-set scheme, but from your
description, you don't have a tree (unless you're looking at
it upside-down).

Celko's book, _SQL for Smarties_, has a short chapter on
handling non-tree graphs.  Also there's a paper on the web
(sorry, don't have the url): "Maintaining Transitive Closure
of Graphs in SQL" (Dong, Libkin, Su & Wong); it gives a lot
of detail about that method.

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