Drew, Stephen wrote:
According to the excellent "Calendrical Calculations" by Reingold &
Dershowitz,
Julian Day 0 = Noon, Monday 1st January 4713 BC (Julian Calendar)
Noon, Monday 24th November -4713 (Proleptic Gregorian
Calendar)
SQLite uses Nov 24, 4714 B.C. (Gregorian) which agrees with the above.
The year -4713 and 4714 B.C. are the same year.
2 = 2 A.D.
1 = 1 A.D.
0 = 1 B.C.
-1 = 2 B.C.
-2 = 3 B.C.
In other words, the year after 1 B.C. is 1 A.D. There is no
year 0 in tranditional year notation.
-----Original Message-----
From: D. Richard Hipp [mailto:[EMAIL PROTECTED]
References and explanations are contained in code comments.
See
http://www.sqlite.org/cvstrac/getfile/sqlite/src/date.c
--
D. Richard Hipp -- [EMAIL PROTECTED] -- 704.948.4565
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