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Hi,
you're sure this command resulted not in an error. As far as I understand the documentation the VIEW keyword is mandatory when creating a view. So this should be:
CREATE VIEW qry_contacts AS
^^^^
My apologies... that was a typo on my part in the email. Indeed, I did use
CREATE VIEW qry_contacts AS...
So, the problem remains...
SELECT c.contact_id, c.firstname, c.lastname, (CASE WHEN (c.firstname & c.lastname) ISNULL THEN 'unnamed' ELSE (c.firstname & ' ' & c.lastname) END) AS fullname, ct.contacttype FROM contacts c LEFT JOIN contacttypes ct ON c.contact_id = ct.contact_id;
Just a first guess of an other newbie...
Greets,
Andre
- -- Andre Vehreschild -- Institute for Scientific Computing, RWTH Aachen Univ.
mailto:[EMAIL PROTECTED] , phone: ++49- 241- 80- 24874
GnuPG-key available at http://www.sc.rwth-aachen.de/vehreschild
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