ahh bugger - google didn't show the new answers had popped up. Pleased I
came up with a working solution though :)


Paul
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skype: r3scue193
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-Forensic Toolkit for SQLite
email from a work address for a fully functional demo licence

On 18 October 2017 at 19:03, jose isaias cabrera <jic...@barrioinvi.net>
wrote:

>
> So simple!  Thanks, Darko.
>
> -----Original Message----- From: Darko Volaric
> Sent: Wednesday, October 18, 2017 1:57 PM
> To: SQLite mailing list
> Subject: Re: [sqlite] Grouping and grabbing one item
>
>
> select (SELECT ed from Tasks where task = 'QUOTE' and Pid = 1),
> max(ed),target, sum(amt) from Tasks where Pid=1 group by target HAVING amt
> > 0;
>
>
> On Oct 18, 2017, at 7:23 PM, jose isaias cabrera <jic...@barrioinvi.net>
>> wrote:
>>
>>
>> CREATE TABLE Tasks (
>> id INTEGER PRIMARY KEY,
>> Pid INTEGER,
>> bd TEXT,
>> ed TEXT,
>> task TEXT,
>> target TEXT,
>> amt REAL
>> );
>>
>> INSERT INTO Tasks (Pid,bd,ed,task,target,amt) VALUES
>> (1,'2017-09-27','2017-09-27','QUOTE','es-ES fr-FR it-IT',0);
>> INSERT INTO Tasks (Pid,bd,ed,task,target,amt) VALUES
>> (1,'2017-09-28','2017-10-01','DOC','es-ES',100);
>> INSERT INTO Tasks (Pid,bd,ed,task,target,amt) VALUES
>> (1,'2017-09-28','2017-10-01','DOC','it-IT',120);
>> INSERT INTO Tasks (Pid,bd,ed,task,target,amt) VALUES
>> (1,'2017-09-28','2017-10-01','DOC','fr-FR',110);
>> INSERT INTO Tasks (Pid,bd,ed,task,target,amt) VALUES
>> (1,'2017-09-28','2017-10-01','VAL','es-ES',70);
>> INSERT INTO Tasks (Pid,bd,ed,task,target,amt) VALUES
>> (1,'2017-09-28','2017-10-01','VAL','fr-FR',75);
>> INSERT INTO Tasks (Pid,bd,ed,task,target,amt) VALUES
>> (1,'2017-09-28','2017-10-01','VAL','it-IT',80);
>> INSERT INTO Tasks (Pid,bd,ed,task,target,amt) VALUES
>> (2,'2017-09-27','2017-09-27','QUOTE','es-ES fr-FR it-IT',0);
>> INSERT INTO Tasks (Pid,bd,ed,task,target,amt) VALUES
>> (2,'2017-09-28','2017-10-01','DOC','es-ES',100);
>> INSERT INTO Tasks (Pid,bd,ed,task,target,amt) VALUES
>> (2,'2017-09-28','2017-10-01','DOC','it-IT',120);
>> INSERT INTO Tasks (Pid,bd,ed,task,target,amt) VALUES
>> (2,'2017-09-28','2017-10-01','DOC','fr-FR',110);
>> INSERT INTO Tasks (Pid,bd,ed,task,target,amt) VALUES
>> (2,'2017-09-28','2017-10-01','VAL','es-ES',70);
>> INSERT INTO Tasks (Pid,bd,ed,task,target,amt) VALUES
>> (2,'2017-09-28','2017-10-01','VAL','fr-FR',75);
>> INSERT INTO Tasks (Pid,bd,ed,task,target,amt) VALUES
>> (2,'2017-09-28','2017-10-01','VAL','it-IT',80);
>>
>> I know I can do,
>>
>> select max(ed),target, sum(amt) from Tasks where Pid=1 group by target
>> HAVING amt > 0;
>>
>> and get,
>>
>> 2017-10-01|es-ES|100.0
>> 2017-10-01|fr-FR|185.0
>> 2017-10-01|it-IT|200.0
>>
>> but, I would like to add the ed of the task='QUOTE' to the beginning of
>> the list.  So, the result would look like this,
>>
>> 2017-09-27|2017-10-01|es-ES|100.0
>> 2017-09-27|2017-10-01|fr-FR|185.0
>> 2017-09-27|2017-10-01|it-IT|200.0
>>
>> I know how to select it by itself,
>>
>> SELECT ed from Tasks where task = 'QUOTE' and Pid = 1;
>>
>> but I need to add it to the beginning of the list with a JOIN or
>> something. Any thoughts?  Thanks.
>>
>> josé
>>
>
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