At 10:10 AM -0700 1/18/06, Robert Simpson wrote:
----- Original Message ----- From: "Marvin K. Bellamy"
<[EMAIL PROTECTED]>
I want to prepare a statement like this one:
SELECT name FROM people WHERE name LIKE '%?%'
But, it looks like host parameters inside string literals aren't
parsed. Any clues as to how I pull this off or if the parameter
really will be parsed?
SELECT name from people WHERE name LIKE ?
Your parameter then should contain the text to look for, such as "%mytext%"
Alternately, and probably more elegantly,
SELECT name FROM people WHERE name LIKE '%' || ? || '%'
-- Darren Duncan
