[EMAIL PROTECTED] wrote:
What are the precedences. If I say:
x COLLATE seq1 || y COLLATE seq2
Does that mean:
(x COLLATE seq1) || (y COLLATE seq2)
Yes, I believe this is the meaning the standard would take. But notice
that you have a dyadic function (concatenation) with two arguments that
have explicit collations that are not equal (seq1 != seq2), so this
should in fact generate a syntax error.
Or does it mean
((x COLLATE seq1) || y) COLLATE seq2
No, I fairly sure that wouldn't be interpreted this way.
I will check the standards syntax specifications and let you know how
they say this should be parsed.
Dennis Cote
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