Yes, you are right. Good thing the OP found it himself. RBS
> actually > > SELECT COUNT(DISTINCT ... > > On 5/1/07, [EMAIL PROTECTED] > <[EMAIL PROTECTED]> wrote: >> It will be as the below query, but replace: >> distinct p.* >> with: >> count(p.ID) >> >> RBS >> >> >> Allan, Mark wrote: >> >> > What I want is Joe Blogs just the once. >> >> > >> >> > >> >> Mark, >> >> >> >> Then try adding distinct like this: >> >> >> >> select distinct p.* >> >> from PatientsTable as p >> >> join ExaminationsTable as e on e.PatientID=p.ID >> >> join TestTable as t on t.ExamID=e.ID >> >> join ForcedSpiroTable as f on f.TestID=t.ID >> >> join RelaxedSpiroTable as r on r.TestID=t.ID >> >> where f.EVC > 2.0 and r.FVC > 2.0; >> > >> > Ok, so here's another question, how would I get the count of patients >> > where the EVC and FVC > 2.0? >> > >> > > > > -- > Puneet Kishor http://punkish.eidesis.org/ > Nelson Inst. for Env. Studies, UW-Madison http://www.nelson.wisc.edu/ > Open Source Geospatial Foundation http://www.osgeo.org/education/ > --------------------------------------------------------------------- > collaborate, communicate, compete > ===================================================================== > > ----------------------------------------------------------------------------- > To unsubscribe, send email to [EMAIL PROTECTED] > ----------------------------------------------------------------------------- > > > ----------------------------------------------------------------------------- To unsubscribe, send email to [EMAIL PROTECTED] -----------------------------------------------------------------------------
