My problem is get a "database is locked" error using lastest linux kernel
(above 2.6.28) , while the code can run smoothly on linux 2.6.26.2
kernel(vmware pc686 host) and on 2.6.26.3 kernel(arm9 embed system).
The problem code is:
#if 1
if (sqlite3_exec(gJcDb, "PRAGMA cache_size = 4000", NULL, NULL, &errMsg) !=
SQLITE_OK)
{
fprintf(stderr, "!!!cache_size set error, %s\n", errMsg);
sqlite3_free(errMsg);
}
#endif
Even if I comment the the #if 0/1 #endif code block, still can't open a
table and access the table data. I tried sqlite3.6.7 and sqlite3.6.16, the
problem is same.
Three attached files are compiling&making sqlite3 Makefile, short test
code(code.c) and test database(jc.db).
Any advise from you will be appreciated!
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