Hi all,
I've got some relatively simple code that does a query and then
does the following:
const char *stmt = "DELETE FROM connect WHERE machine = 'xxx';" ;
printf ("Before : %s\n", sqlite3_errmsg (pdb)) ;
sqlite3_exec (pdb, stmt, NULL, NULL, NULL) ;
printf ("After : %s\n", sqlite3_errmsg (pdb)) ;
The query that happens before this works as expected and then the
above results in:
Before : not an error
After : unable to open database file
Obviously, at the 'Before', the database was open and valid so I
don't understand why it returns a database not open error after the
sqlite_exec() statement.
I'm using the default sqlite libs on Ubuntu Hardy:
ii libsqlite3-0 3.4.2-2 SQLite 3 shared library
ii libsqlite3-dev 3.4.2-2 SQLite 3 development files
Anyone have any clues as to what could be going on here?
Cheers,
Erik
--
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Erik de Castro Lopo
http://www.mega-nerd.com/
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