Hi, why this code consume free memory ? the same code but 'UPDATE' works fine....
any help? #include <stdio.h> #include <stdlib.h> #include "sqlite3.h" int main(int argc, char **argv) { sqlite3 *db; char *zErrMsg = 0; int rc; char st1[200]; sqlite3_initialize(); // sprintf (st1,"UPDATE Table1 SET Temp = %d WHERE Id = %d",1,1); sprintf (st1,"INSERT INTO Table1 (Id, Temp,Data) VALUES (%d,1,'1234')",1); sqlite3_soft_heap_limit(10); rc = sqlite3_open("pippo.sqlite", &db); if( rc ) { fprintf(stderr, "Can't open database: %s\n", sqlite3_errmsg(db)); sqlite3_close(db); exit(1); } rc = sqlite3_exec(db,"PRAGMA cache_size=0;", 0, 0, &zErrMsg); if( rc!=SQLITE_OK ) { fprintf(stderr, "SQL error: %s\n", zErrMsg); sqlite3_free(zErrMsg); } rc = sqlite3_exec(db,"CREATE TABLE Table1(Id INTEGER,Temp INTEGER,Data TEXT);", 0, 0, &zErrMsg); if( rc!=SQLITE_OK ) { fprintf(stderr, "SQL error: %s\n", zErrMsg); sqlite3_free(zErrMsg); } do { rc = sqlite3_exec(db,st1, 0, 0, &zErrMsg); if( rc!=SQLITE_OK ) { fprintf(stderr, "SQL error: %s\n", zErrMsg); sqlite3_free(zErrMsg); } } while (1); sqlite3_close(db); return 0; } -- View this message in context: http://old.nabble.com/sqlite-memory-consume..-tp28068504p28068504.html Sent from the SQLite mailing list archive at Nabble.com. _______________________________________________ sqlite-users mailing list sqlite-users@sqlite.org http://sqlite.org:8080/cgi-bin/mailman/listinfo/sqlite-users