Great! This works better than mine suggestion.
/Patrik

On 06/23/2012 07:12 PM, Petite Abeille wrote:
> 
> On Jun 23, 2012, at 6:55 PM, Patrik Nilsson wrote:
> 
>> select id,count(*) from repetitionhistory where count(id)<3 group by id
> 
> select id,count(*) from repetitionhistory group by id having count(id)<3 
> 
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