Are you forming your query with sprintf? It may be worth printing the query you are preparing, to make sure it says what you think it is.
Thanks, Kev Sent from my iPhone > On 3 Jun 2014, at 14:53, Micka <mickamus...@gmail.com> wrote: > > Hi, > > I'm having trouble with the percent character ..... > > > By example in my table I have : > > id name > 1 micka > 2 mickael > > I would like to do that : > > Select * from table name where name LIKE '%micka%' > > with my linux c program, the result is 0 > > but with the sqlite3 command program it works .... > > I also tested this : > > Select * from table name where name LIKE 'micka%' > > and this time, it works in my linux c program ... > > Why ? > _______________________________________________ > sqlite-users mailing list > sqlite-users@sqlite.org > http://sqlite.org:8080/cgi-bin/mailman/listinfo/sqlite-users _______________________________________________ sqlite-users mailing list sqlite-users@sqlite.org http://sqlite.org:8080/cgi-bin/mailman/listinfo/sqlite-users
