You are converting the "start of day" (UTC) to "localtime". Your timezone is 
obviously 4 hours behind UTC...

asql> SELECT datetime('now'), datetime('now','localtime'),datetime('now','start 
of day'),datetime('now','localtime','start of day'),datetime('now','start of 
day','localtime');
                           datetime('now') = 2015-07-29 06:28:59
               datetime('now','localtime') = 2015-07-29 08:28:59
            datetime('now','start of day') = 2015-07-29 00:00:00
datetime('now','localtime','start of day') = 2015-07-29 00:00:00
datetime('now','start of day','localtime') = 2015-07-29 02:00:00

-----Urspr?ngliche Nachricht-----
Von: jose isaias cabrera [mailto:jicman at cinops.xerox.com]
Gesendet: Mittwoch, 29. Juli 2015 07:04
An: sqlite-users at mailinglists.sqlite.org
Betreff: [sqlite] datetime start of day result


Greetings!

if I run this command on the sqlite3 command tool,

select datetime('now','localtime');

I get,

sqlite> select datetime('now','localtime');
2015-07-29 00:48:07

which is correct.  When I run this command,

sqlite> select datetime('now','start of day','localtime');
2015-07-28 20:00:00

I am expecting 2015-07-29 00:00:00.  What does 'start of day' does/means?
Thanks.

jos?

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