> so that one can find more than one row for the same values of (Id,Date)?
Yes and that messes up your idea. Solution is to tidy that table up first
before running any select SQL.

> Average, last one, largest one?
For now I have taken the largest one as in R Smith's SQL. Probably it is
better to keep the last value, so the one with the highest ROWID.

RBS

On Fri, Oct 21, 2016 at 7:59 PM, Jean-Luc Hainaut <
jean-luc.hain...@unamur.be> wrote:

> > I had a look at this and tried it without using the extra auto-increment
> field, using the table ROWID
> > instead to check for consecutiveness. It would work great and a lot
> faster indeed if it wasn't for
> > the multiple values on the same date. Problem with that is that if you
> group by date it may
> > skip a ROWID, so it won't pick up that triple. The answer is just to
> clean that table up and
> > clear these extra values on the same day. This will always need to be
> done in any case, so
> > it might as well be done as a one off rather than in every select SQL.
> Thanks for that idea,
> > it looks to me the fastest. RBS
>
> With a complexity of O(N.logN) this algorithm is the second best to a pure
> sequential scan that compares the successive triples, which is in O(N).
> Practically, considering the locality of accesses for the join (the 3 rows
> to join most often are in the same page) and the small size of the primary
> index, the performance should be close to that of a sequential scan.
>
> When you write "if it wasn't for the multiple values on the same date", do
> you mean that the values of (Id,Date) are not unique among the rows of
> TABLE1, so that one can find more than one row for the same values of
> (Id,Date)? In this case, how do you compute the unique Value of this couple
> (Id,Date)? Average, last one, largest one?
>
> JLH
>
>
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