Try instead of "SELECT * FROM table WHERE name LIKE ?" as your sql query,
"SELECT * FROM table WHERE name LIKE :comparison"
Thomas Zangl wrote:
Vitali Lovich schrieb:
Regarding your code snippet:
// SQL Statement is: "SELECT * FROM table WHERE name LIKE ?"
search = '%test%';
sqlite3_bind_text(prepared_statement, 0,search , search ,
SQLITE_STATIC);
First I'm not sure what language you're using - it seems Perl-like.
Anyways, the documentation for
http://www.sqlite.org/capi3ref.html#sqlite3_bind_text gives the 4th
param as the number of bytes (not chars) while you're passing the
original string. Since I'm assuming it's Perl, it won't generate an
error on the type mismatch. You generally want to pass -1 for the
fourth parameter (from what I understand, -1 is always safe for
sqlite3_bind_text). Also, take care in using SQLITE_STATIC and make
sure that the string you pass remains on the heap (i.e. delete isn't
called, not sure if this is possible in Perl) or the stack (i.e.
local variable in scope) when you execute the statement.
Its C :-)
Anyway, I tried your suggestion and free the char* after
sqlite3_finalize. Does not help.
char* sql_parameter_search = '%test%'
rc = sqlite3_bind_text(prepared_statement, 1,
sql_parameter_search, strlen(sql_parameter_search),
SQLITE_STATIC);
sql_check_result(rc);
logDebug("Added search = %s", sql_parameter_search);
the result is:
Added search = %test%
my_sqlite_logger-SQLITE said: (0) SELECT * FROM table WHERE name LIKE ?
So - no variable substitution done?
Somebody with a working LIKE example?
TIA,
Thomas
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