On Fri, Jul 2, 2010 at 11:19 AM, P Kishor <punk.k...@gmail.com> wrote: > On Fri, Jul 2, 2010 at 11:19 AM, P Kishor <punk.k...@gmail.com> wrote: >> On Fri, Jul 2, 2010 at 11:15 AM, Peng Yu <pengyu...@gmail.com> wrote: >>> Hi, >>> >>> SELECT DISTINCT type_id FROM foods; >>> >>> If I use 'distinct', any entry that shows up greater or equal to one >>> time will only appear once. But I want to select an entry that appears >>> <=n times and only show n times if it appears more than n times. I >>> think that "group by" might help. But I'm not familiar with SQL enough >>> yet. Would you please let me know what command to use? >>> >> >> Try >> >> SELECT <whatever column>, Count(type_id) >> FROM foods >> GROUP BY <whatever column> >> HAVING Count(type_id) < n > > make that > > HAVING Count(type_id) <= n
But this doesn't show anything that count more than n times. I want the type_id shows up more than n times in the database only appear n times in the result of the query. -- Regards, Peng _______________________________________________ sqlite-users mailing list sqlite-users@sqlite.org http://sqlite.org:8080/cgi-bin/mailman/listinfo/sqlite-users
