Quoth Jeff Archer <jsarc...@nanotronicsimaging.com>, on 2010-11-13 11:20:51 
-0800:
> And I can get the number of unique Y offsets in a pattern like so:
> 
> SELECT COUNT(Offset_Y) FROM (SELECT DISTINCT Offset_Y FROM Tiles WHERE 
> PatternID 
> = 1);
> 
> Is it possible to have a single query that will generate a row for each 
> PattenID, COUNT(Offset_Y) combination?

Does SELECT PatternID, COUNT(DISTINCT Offset_Y) FROM Tiles GROUP BY
PatternID do what you're looking for?

   ---> Drake Wilson
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