Hi Jim,

On Nov 20, 2010, at 6:52 PM, Jim Morris wrote:

>> This should return a the equivalent keys in the two maps.  The basic
>> idea is to compare the values in each key in foo(left outer join foo)
>> with the values for each key in bar where there are any matching
>> values(left outer join bar) and only select those with a complete match(
>> inner join).  Not sure this is the most efficient way.

Clever :) Thank you very much.

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