On 10-01-11 08:42, Sven wrote: > Dear SQLite users, > > I've created a Microsoft Access 2003 database with three complex queries > written in pure SQL language. The function of the database is to > document and calculate the daily work-time. > > Today I want to convert this database to SQLite but I have problems with > my written queries: How can I calculate the difference of two times and > show the result as double value? > > For more information I'll include one example: One table hold the two > times (start_time, end_time) and the calculated result (shown in the > table as 'difference'): > > [code] > start_time | end_time | difference > 08:00:00 | 16:30:00 | 8.5 > [/code] > > The result of the difference between the two times (start_time, > end_time) shown in the table above as 'difference' will be calculated > with the following SQL-query code within Microsoft Access 2003: > > [code] > ( [end_time] - [start_time] ) * 24 > [/code] > > and returns the following data '8.5'. While using the following query > code within SQLite: > > [code] > select time(end_time) - time(start_time) > [/code] > > I only get the following data returned: '8' (but not '8.5' as calculated > with SQL). > > So currently I don't know what to do next to solve my problem and > perhaps all the other users of this SQLite-users mailing list could help > me out. > > best regards select (strftime('%s', time('now', '4 minutes')) - strftime('%s', time('now'))); returns: 240 (4*60)
This was found via Google at: http://www.mail-archive.com/sqlite-users@sqlite.org/msg56060.html More help on the strftime function: http://sqlite.org/lang_datefunc.html http://pubs.opengroup.org/onlinepubs/007908799/xsh/strftime.html -- Luuk _______________________________________________ sqlite-users mailing list sqlite-users@sqlite.org http://sqlite.org:8080/cgi-bin/mailman/listinfo/sqlite-users