On 01/22/2015 11:53 AM, Sairam Gaddam wrote:
I have one doubt regarding sqlite code. I have 2 programs-one with sqlite3_exec() included in the code and in other it is not included.I included those files which are zmain.c and zmain1.c respectively. First i created a database and added a table "em" and added some contents to it,then i executed and prepared the sqlite select query. I added "printf("result");" in the "case op_resultrow" of the function sqlite3vdbeexec(). Here when i executed zmain.c, sqlite3_prepare_v2(db, sql, strlen(sql) + 1, &selectStmt, NULL); the above statement didn't print anything.OUTPUT: database opened successfully result result result result Operation done successfully Before Afterprep (clearly there is nothing between before and afterprep) But when i commented the sqlite3_exec() in zmain1.c due to sqlite_prepare_v2() function,the program somehow entered sqlite3vdbeexec() and printed what i gave in my printf statement. OUTPUT: database opened successfully Operation done successfully Before result result Afterprep (clearly there are some output between before and afterprep) My doubt is why the function call sqlite3_prepare_v2() called sqlite3vdbeexec in second case and why not in first program.
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The first call to sqlite3_prepare_v2() needed to load the database schema into memory. It does this by executing a regular "SELECT ..." statement on the sqlite_master table, which involves calling sqlite3VdbeExec(). Via sqlite3_exec(), as it happens.
Dan.
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