Yup. The default configuaration already have the nathelper.so loaded. Plus, there are other places in the config where nat_uac_test was called but never error out.
On Thu, Jan 3, 2019 at 5:39 PM Sergey Okhapkin <s...@sokhapkin.dyndns.org> wrote: > Did you load the module? > > On Thursday, January 3, 2019 5:27:12 PM EST Andrew Chen wrote: > > Hey it's me again. > > > So I'm following the instructions in the Kamailio 5.1.x wiki module page > for websocket configuration and it specifically mention to set this block: > > > onreply_route[WS_REPLY] { > > xlog("L_INFO", "[CSeq $cs] Is in WS_REPLY."); > > xlog("L_INFO", "[CSeq $cs] Sending $rs $rr to $sel(via[2].host) > via $sel(via[2].transport) len: $ml"); > > xlog("L_INFO", "[CSeq $cs] \n$mb \n"); > > > if(nat_uac_test("64")) { > > # Do NAT traversal stuff for replies to a WebSocket > connection > > # - even if it is not behind a NAT! > > # This won't be needed in the future if Kamailio and the > > # WebSocket client support Outbound and Path. > > add_contact_alias(); > > } > > } > > > When I did this and started up Kamailio, it gave me an error: > > > Jan 3 22:19:43 sjomainkama55 kamailio: ERROR: <core> [core/cfg.y:3309]: > yyparse(): cfg. parser: failed to find command nat_uac_test (params 1) > > > I moved that if statement to a route block and I was able to start it up. > > > The wiki page for nathelper module specify this function can be run in > onreply_route as well: > > > > 5.5. nat_uac_test(flags) > > Tries to guess if client's request originated behind a nat. The parameter > determines what heuristics is used. > > Meaning of the flags is as follows: > > - 1 - The “Contact” header field is searched for occurrence of RFC1918 > or RFC6598 addresses. > - 2 - the "received" test is used: address in the “Via” header is > compared against source IP address of signaling > - 4 - The Top Most “Via” is searched for occurrence of RFC1918 or > RFC6598 addresses > - 8 - The SDP is searched for occurrence of RFC1918 or RFC6598 > addresses > - 16 - Test if the source port is different from the port in > the “Via” header > - 32 - Test if the source IP address of signaling is a RFC1918 or > RFC6598 address > - 64 - Test if the source connection of signaling is a WebSocket > - 128 - Test if the “Contact” header URI port differs from the source > port of the request (Warning: this is might be legal or even intended > combination in non NATted scenarios) > > All flags can be bitwise combined, the test returns true if any of the > tests identified a NAT. > > This function can be used from REQUEST_ROUTE, ONREPLY_ROUTE, > FAILURE_ROUTE, BRANCH_ROUTE. > > > is this some known bug in 5.1.x? > > Thanks > > > -- > > Andy Chen > > achen@ <ac...@thinkingphones.com>fuze.com > > > > > *Confidentiality Notice: The information contained in this e-mail and any > attachments may be confidential. If you are not an intended recipient, you > are hereby notified that any dissemination, distribution or copying of this > e-mail is strictly prohibited. If you have received this e-mail in error, > please notify the sender and permanently delete the e-mail and any > attachments immediately. You should not retain, copy or use this e-mail or > any attachment for any purpose, nor disclose all or any part of the > contents to any other person. Thank you.* > > > > _______________________________________________ > Kamailio (SER) - Users Mailing List > sr-users@lists.kamailio.org > https://lists.kamailio.org/cgi-bin/mailman/listinfo/sr-users > -- Andy Chen Sr. Telephony Lead Engineer 415 516 5535 (M) achen@ <ac...@thinkingphones.com>fuze.com -- *Confidentiality Notice: The information contained in this e-mail and any attachments may be confidential. If you are not an intended recipient, you are hereby notified that any dissemination, distribution or copying of this e-mail is strictly prohibited. If you have received this e-mail in error, please notify the sender and permanently delete the e-mail and any attachments immediately. You should not retain, copy or use this e-mail or any attachment for any purpose, nor disclose all or any part of the contents to any other person. Thank you.*
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