After spending more hours of unsuccessful debugging, I can add to my problem:
My call enters the branch_route_failure route, where I can get the 486 status
with t_get_status_code(). However, I cannot issue a t_reply() in this phase of
the call. And after some more seconds, when the transaction times out (looks
like it's the no-answer-received timer of 30 seconds), Kamailio just sends a
408 without entering any route anymore. I have a debug output in my failure
route, which is never printed.
I tried virtually every command from tm or tmx module in the last hours that
looked like it could help. Without success. Still stuck at "Why is there
another branch after t_suspend and t_continue and how do I make it go away?
There's just an evapi call to cgrates in between.
Grateful for any ideas.
Thanks,
Sebastian
----- Ursprüngliche Mail -----
Von: "Sebastian Damm" <sd...@pascom.net>
An: "sr-users" <sr-users@lists.kamailio.org>
Gesendet: Dienstag, 23. November 2021 17:51:02
Betreff: [SR-Users] t_suspend() / t_continue() create new branches
Hi,
I have the following weird problem. A Kamailio (5.4.x) with some asynchronous
permission logic suspends outgoing INVITEs and resumes them after the answer of
the permission system. Everything works as expected when the call is answered.
However, when the called party rejects the call (with a 486 for example), the
call doesn't get torn down immediately (it is rejected with a 408 eventually)
because Kamailio logs the following:
Nov 23 14:51:02 host /usr/sbin/kamailio[1569]: DEBUG: app_python
[apy_kemi.c:106]: sr_kemi_config_engine_python(): execution of route type 4
with name [ksr_onreply_manage] returned 1
Nov 23 14:51:02 host /usr/sbin/kamailio[1569]: DEBUG: tm [t_reply.c:1363]:
t_should_relay_response(): ->>>>>>>>> T_code=183, new_code=486
Nov 23 14:51:02 host /usr/sbin/kamailio[1569]: DEBUG: tm [t_reply.c:1448]:
t_should_relay_response(): store - other branches still active
Nov 23 14:51:02 host /usr/sbin/kamailio[1569]: DEBUG: tm [t_reply.c:1926]:
relay_reply(): reply status=3 branch=2, save=1, relay=-1 icode=0 msg status=486
I don't do any forking, the call is just forwarded.
I put the following line immediately after t_suspend() and in the beginning of
the route specified in t_continue():
KSR.info("We're at branch index %d" % KSR.pv.get("$T(branch_index)"))
This produces the following output:
Nov 23 16:30:13 host /usr/sbin/kamailio[2745]: INFO: <core> [core/kemi.c:104]:
sr_kemi_core_info(): We're at branch index 0
Nov 23 16:30:13 host /usr/sbin/kamailio[2725]: INFO: <core> [core/kemi.c:104]:
sr_kemi_core_info(): We're at branch index 2
So apparently, the suspend and continue introduce new branches. (Other option:
I'm doing something completely different creating those branches, but I don't
have any append_branch() or similar in my code.)
I assume, I just missed a configuration parameter. Can I get Kamailio somehow
to behave as if there was just one branch and forward the negative reply?
Thanks,
Sebastian
__________________________________________________________
Kamailio - Users Mailing List - Non Commercial Discussions
* sr-users@lists.kamailio.org
Important: keep the mailing list in the recipients, do not reply only to the
sender!
Edit mailing list options or unsubscribe:
* https://lists.kamailio.org/cgi-bin/mailman/listinfo/sr-users
__________________________________________________________
Kamailio - Users Mailing List - Non Commercial Discussions
* sr-users@lists.kamailio.org
Important: keep the mailing list in the recipients, do not reply only to the
sender!
Edit mailing list options or unsubscribe:
* https://lists.kamailio.org/cgi-bin/mailman/listinfo/sr-users
