From: Oleg Nesterov <[email protected]>
Subject: proc: actually make proc_fd_permission() thread-friendly
The commit 96d0df79f264 ("proc: make proc_fd_permission() thread-friendly")
fixed the access to /proc/self/fd from sub-threads, but introduced another
problem: a sub-thread can't access /proc/<tid>/fd/ or /proc/thread-self/fd
if generic_permission() fails.
Change proc_fd_permission() to check same_thread_group(pid_task(), current).
Fixes: 96d0df79f264 ("proc: make proc_fd_permission() thread-friendly")
Reported-by: "Jin, Yihua" <[email protected]>
Signed-off-by: Oleg Nesterov <[email protected]>
Cc: "Eric W. Biederman" <[email protected]>
Cc: <[email protected]>
Signed-off-by: Andrew Morton <[email protected]>
---
fs/proc/fd.c | 14 +++++++++++---
1 file changed, 11 insertions(+), 3 deletions(-)
diff -puN fs/proc/fd.c~proc-actually-make-proc_fd_permission-thread-friendly
fs/proc/fd.c
--- a/fs/proc/fd.c~proc-actually-make-proc_fd_permission-thread-friendly
+++ a/fs/proc/fd.c
@@ -291,11 +291,19 @@ static struct dentry *proc_lookupfd(stru
*/
int proc_fd_permission(struct inode *inode, int mask)
{
- int rv = generic_permission(inode, mask);
+ struct task_struct *p;
+ int rv;
+
+ rv = generic_permission(inode, mask);
if (rv == 0)
- return 0;
- if (task_tgid(current) == proc_pid(inode))
+ return rv;
+
+ rcu_read_lock();
+ p = pid_task(proc_pid(inode), PIDTYPE_PID);
+ if (p && same_thread_group(p, current))
rv = 0;
+ rcu_read_unlock();
+
return rv;
}
_
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