You can get all the parameters with request.getQueryString();
http://java.sun.com/products/servlet/2.2/javadoc/javax/servlet/http/HttpServletRequest.html
Matt
--- Web Programmer <[EMAIL PROTECTED]> wrote:
> This gives only part of the URL - part before the "?".
> I want the entire URL including the part after the
> "?" of the previous page.
>
> For example, if I were to use getParameters() would
> give those of the target page, what do you do to get
> those parameters of the previous page.
>
> --- Billy Talton <[EMAIL PROTECTED]> wrote:
> > See the servlet 2.2 API... specifically the HttpUtil
> > package.
> >
> > -----Original Message-----
> > From: Web Programmer
> > [mailto:[EMAIL PROTECTED]]
> > Sent: Friday, July 20, 2001 7:34 AM
> > To: [EMAIL PROTECTED]
> > Subject: How to get the entire URL of referring page
> >
> > Hi All!
> >
> > I am trying to capture of the entire URL of where
> > the
> > user has come from - i.e., the URL of the previous
> > page. I am getting null value when I invoke the
> > getReferrer() method.
> >
> > Thanks.
> >
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