Hi Mike, I tested both with IE 6.0 and Netscape 4.5.
Both give the same problem.

Any idea whether I'm sending the CRLF correctly ?

Thanks.
Marli.


At 07:49 AM 11/29/2001 -0800, SCHACHTER,MICHAEL (HP-NewJersey,ex2) wrote:
>Hi,
>
>What browser are you using to submit the form? Also,
>you may already be aware, but as mentioned by the
>other reply there's an easy way to handle multipart
>form data in Struts, you can check out the struts-upload
>webapp in the distribution for an example.
>
>As with your use of MultipartIterator, I'm not sure what
>the problem could be there.
>
>-----Original Message-----
>From: Marli Satyadi [mailto:[EMAIL PROTECTED]]
>Sent: Wednesday, November 28, 2001 8:23 PM
>To: [EMAIL PROTECTED]
>Subject: File Upload Problem.
>
>
>Hello,
>
>I was writing some upload code to test the use of  MultipartIterator class.
>
>My html code is as follows:
>-----------------------------------------
><BODY BGCOLOR="FFFFFF">
><h1> MULTIPART TEST</h1>
><FORM NAME="loadfile"
>ACTION="/MDC/servlet/servlet/com.cisco.nm.callhome.servlet.TestServlet"
>ENCTYPE='multipart/form-data' METHOD="POST">
>
>CLASS: <INPUT NAME=class TYPE=text VALUE="File">
><br>
>COMMAND: <INPUT NAME=cmd TYPE=text VALUE="Add">
><br>
>DATA (XML): <textarea name="dataParam" rows=20 cols=80></textarea>
><br>
>File Location: <INPUT TYPE=file  NAME="uploadfile" SIZE="50">
><br>
><INPUT TYPE=SUBMIT NAME=SUBMIT>
></FORM>
></BODY>
></HTML>
>
>
>My servlet code is as follows:
>-------------------------------------------
>          protected void doPost(HttpServletRequest req, HttpServletResponse
>resp)
>          throws ServletException, java.io.IOException
>          {
>               LogUtil.debug(_Class, " -----> DO POST");
>               MultipartIterator iter = new MultipartIterator(req, 64*1024,
>Integer.MAX_VALUE, "C:/Temp");
>
>               MultipartElement elem = null;
>               while( (elem = iter.getNextElement()) != null )
>               {
>                  if( elem.isFile() )
>                  {
>                     System.out.println("ELEM is a file");
>                     System.out.println("FILENAME = " + elem.getFileName());
>                     System.out.println("FILE PATH = " +
>elem.getFile().getAbsolutePath());
>                  }
>                  else {
>                     System.out.print("NAME = '" + elem.getName() + "'");
>                     System.out.println(". VALUE = '" + elem.getValue() +
>"'");
>                     //System.out.println(elem.getName() + " = " +
>elem.getValue());
>                  }
>               }
>
>          }
>
>When I use my browser to the html file, put some data in the "dataParam"
>text area and
>hit Submit,  I got the following result in Tomcat stdout.log
>
>NAME = 'class'. VALUE = 'File'
>NAME = 'cmd'. VALUE = 'Add'
></File>'</AuthTuple>sword>bejo</Password>1663eb7d56063ec67f23be</Checksum>
>ELEM is a file
>FILENAME = ch-p506-2_enable_callhome.cfg
>FILE PATH = C:\Temp\strts4674.tmp
>NAME = 'SUBMIT'. VALUE = 'Submit Query'
>
>My question is:
>----------------------
>* Is there an explanation on why the "dataParam" parameter is not printed
>out,
>or printed out but has the wrong value ?
>* I also have written a Java multipart writer to test it, but it looks like
>that the file is always
>    larger by 2 bytes. Isn't the format for multipart request like this:
>    --Boundary\r\n
>    content-disposition: form-data; name="blah"; filename="file.txt"\r\n
>    Content-type: application/octet-stream\r\n
>     \r\n
>     Body goes here......
>    --Boundary--\r\n
>    Am I correct about the CRLF (\r\n) ? I have read RFC 1867 and RFC 2046
>and it looks correct.
>    Any ideas ?
>
>Thanks in advance.
>Marli.
>
>
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