If I understood you right: The STARTUP script is in the C:\jakarta-tomcat-4.0.1\bin directory.
If you are not directly in the \bin directory when you run it, you will need to include C:\jakarta-tomcat-4.0.1\bin somewhere in your path. Hope that helps. -- Geoff -----Original Message----- From: kuma.cra [mailto:[EMAIL PROTECTED]] Sent: Friday, December 28, 2001 9:09 AM To: Struts Users Mailing List Subject: Please can someone post an example of there Environment setup 4 tomcat 4 I have deleted the previous install of tomcat 3.2.3 I have installed tomcat 4 . Thus in my environment set-up i have the following Tomact unarchived and resides in C:\jakarta-tomcat-4.0.1 rem set %CATALINA_HOME%\bin\startup set CATALINA_HOME=C:\jakarta-tomcat-4.0.1 set ANT_HOME=C:\ant\jakarta-ant-1.3 set classpath=%ANT_HOME%\lib\ant.jar set PATH=%PATH%;%ANT_HOME%\bin set JAVA_HOME=C:\JDK1.3 Thus on running /DOUBLE-CLICK the script STARTUP get a Bad command or file name"on my Windows 98 Box. I have tiried various combo paths to no avail example below set TOMCAT_HOME=C:\jakarta-tomcat-4.0.1 set classpath=%TOMCAT_HOME%\bin set PATH=%PATH%;%TOMCAT_HOME%\bin set JAVE_HOME=C:\JDK1.3 Also tried and checked the three most common / likely reasons in the userguide . Nevertheless i assume it is my path any suggestions or can someone post an example of there Win98 Environment variable in Autoexec.bat Cheers Chuck Amadi -- To unsubscribe, e-mail: <mailto:[EMAIL PROTECTED]> For additional commands, e-mail: <mailto:[EMAIL PROTECTED]>