Huh? How come nobody noticed this before?
Shouldn't the for statement be like this:
---------------------------------------------------------------------
for (var n = startFrom; n < argvalue.length; n++) {
if (validChars.indexOf(argvalue.substring(n, n+1)) == -1)
return false;
}
Assigning var n =0; doesn't make sense to me ....
----------------------------------------------------------------------
function isAllDigits(argvalue) {
argvalue = argvalue.toString();
var validChars = "0123456789";
var startFrom = 0;
if (argvalue.substring(0, 2) == "0x") {
validChars = "0123456789abcdefABCDEF";
startFrom = 2;
} else if (argvalue.charAt(0) == "0") {
validChars = "01234567";
startFrom = 1;
}
for (var n = 0; n < argvalue.length; n++) {
if (validChars.indexOf(argvalue.substring(n, n+1)) == -1)
return false;
}
return true;
}
-------------------------------------------------------------
-----Original Message-----
From: Yansheng Lin [mailto:[EMAIL PROTECTED]
Sent: June 18, 2003 4:23 PM
To: 'Struts Users Mailing List'
Subject: RE: Validator problem with integers
Oh yeah. Sorry
Well, at least I pinpointed where the check failed:).
>There is a js function called isAllDigits(arg) in validator-rules.xml.
>It's
>used by validateInteger(). You can use that.
No you can't because that function validates based on the type of number
(int, octal, etc).
David
>
>Yan
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