John,

I don't think you have the right approach.   I just went through this for
making globes and this is what I came up with:

The radius of the lattitude circle in question is a function of the radius
earth.  That is,

radius of x degree lattitude = cos(lattitude) *radius at equator.

If the earth had a radius of 4000 miles, then the 45 degree circle radius
would be 2828.427 miles.  And a degree at that lattitude would be 2828.427 *
2pi/360 or 49.365366 miles.  (Of course, I mean along the lattitude circle)

++ron




-----Original Message-----
From: John Carmichael <[EMAIL PROTECTED]>
To: [email protected] <[email protected]>
Date: Friday, August 20, 1999 12:17 PM
Subject: length of degs./mins./secs.


>Hello dialists:
>
>I've had another basic question that has bothered me for a while. In fact,
>it is such an elementary question that I'm almost embarassed to ask it, but
>as they say, no question is a dumb, just the person who asks it! And I know
>none of you are judgemental.
>
>I am trying to come up with a simple formula for determining the length of
a
>degree of longitude at a specific latitude. I wish someone of you would
>check my reasoning and my math to see if my conclusions are correct.
>
>I am basing my calculations on the premise (true or false?) that the length
>of a degree of longitude is directly proportional to the latitude because
>the length of a degree of longitude is maximum at the equator (90* or
111.32
>km.) and zero at the poles. (to obtain 111.32 km. as the length of one
>degree longitude at the equator, I divided the circumference of the earth
by
>360 degrees: 111.32 km./degree=40,074.16 km./360*)
>
>For example, if 45* latitude (north or south) is one half the distance from
>the pole to the equator, then the length of one degree of longitude at 45*
>latitude would be equal to one half the length of a degree of longitude at
>the equator. This is 111.32 km./ 2 = 55.66 km. Is this correct?
>
>Using similar logic, if I wanted to know the length of one degree of
>longitude at latitude 32* 13' 18", first I need to convert this latitude to
>decimals. This would be: 32.2216*.
>Then I determine the percentage of the distance this latitude is from the
>pole to the equator.  This is: (90*-32.2216*)/90*=.64198 or 64.2%.  64.2%
of
>111.32 km. = 71.46 km.
>Is this correct?
>
>32* 13' 18" is the latitude for Tucson Arizona as given by Fer in his
>sundial program in his list of world cities and their coordinates.  I
>wondered to which part of the city these coordinates refered.  Was it City
>Hall, The main plaza, the geographical center or what? (Fer, if you are
>reading this would you let us know?)
>
>If one degree of longitude at this latitude is 71.46 km. then one minute of
>longitude is 71.46*/60'/deg.=1.19 km, and one second of longitude is
>1.198km./60"/min.=.01985km.=19.85 meters.  Correct?
>
>The length of a degree of latitude is the same everywhere on earth. It
would
>equal the circumference of the earth divided by 360. This is 111.32 km.,
the
>same length as a degree of longitude at the equator. This makes the length
>of a minute of latitude=111.32 km./60'/deg.=1.855 km., and one second of
>latitude is 1.855 km./60"/min.= .03092 km.=30.92 meters.
>
>If this is so, then Fer's coordinates are accurate to 30 meters of latitude
>and 20 meters of longitude at Tucson's latitude.  Am I correct?
>
>This leads me to ask if this degree of precision and accuracy even
>necessary. I doubt that it would even be possible to build a sundial to
>these exacting requirements.  When dialists label their sundials with
>latitude and longitudes accurate to the second, is this not presumtious, or
>are they just giving the precise coordinates of the place in which the
>sundial is located?
>
>I think this is an important concept for all dialists to understand,
>especially the beginners. You might have delt with this before I joined the
>list, but I'm sure most of us who are newcomers would appreciate a replay
of
>the thread.
>
>Thanks so much,
>John Carmichael
>http://www.azstarnet.com./~pappas
>
>

Reply via email to