May I suggest you to have a look at Orologi Solari ?

It includes two different tools for wall declination measurement.

It could maybe help you.

Greetings.

Gian

http://digilander.libero.it/orologi.solari



 
----Messaggio originale----
Da: ka...@karonadams.com
Data: 01/08/2011 17.36
A: "Bill Gottesman"<billgottes...@comcast.net>, <sundial@uni-koeln.de>
Ogg: RE: Azimuth calculation/Wall declination

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THIS is the kind of thing I have been looking for! The kinds of techniques that 
make the complex math work simply.
 
Cathedrals were built a thousand years ago by people who had little more 
literacy than needed to do their jobs. None of them knew what a sine or cosine 
or tangent was. They knew how ratios worked and they knew the practicalities of 
geometry.
 
Thanks for the great tool. As it happens, I need to measure the declination of 
a wall and this helps a lot!
 

Karon Adams
Accredited Jewelry Professional (GIA)
You can send a free Rosary to a soldier!
www.facebook.com/MilitaryRosary
www.YellowRibbonRosaries.com
 



From: sundial-boun...@uni-koeln.de [mailto:sundial-boun...@uni-koeln.de] On 
Behalf Of Bill Gottesman
Sent: Monday, August 01, 2011 10:55 AM
To: sundial@uni-koeln.de
Subject: Re: Azimuth calculation/Wall declination
 
About 10 years ago I worked out a simple method to measure wall declination 
using just a carpenter's square and an accurate watch.  The methods is 
described here http://www.precisionsundials.com/wall%20declination.pdf, and a 
simple windows program that does all the calculations for you is here 
http://www.precisionsundials.com/walldeclination.exe.  When I tested it out 
many years ago, I believe it gave results repeatable at different times and on 
different days to a few tenths of a degree.

-Bill

On 7/31/2011 9:57 AM, Andrew Theokas wrote: 



Fellow dialists:

 

I am using the following well known formula to calculate the sun’s azimuth for 
a particular time and location:

 
Azimuth= tan-1    (sin H/(sin φ*cos H – cos φ*tanδ)
 
where 
H= Sun’s hour angle
φ= the latitude - 42.3 degrees
δ is the sun’s declination - 18.62 degrees
 
The location is in Boston, USA or 42.3 degrees N and 71.04 degrees west
 
I am using the azimuth-azimuth approach to find the declination of a wall found 
here:
 
http://www.mysundial.ca/tsp/wall_declination.html
 
the time the measurement was made was 11:18 am (daylight savings time is in 
effect)
 
I can easily calculate that the azimuth with respect to the wall is 26.8 
degrees.
 
Here is the problem: using two other independent methods I find that the wall’s 
declination is 20 degrees East.
 
So 26.8 degrees – Sun’s Azimuth should equal about twenty degrees.
 
But, using the above equation I cannot get an Azimuth value to work. One place 
where I might be in error is the value of the Hour angle which I compute to be 
about –16 degrees.
 
But you can also find the Hour Angle on line here at 
http://pveducation.org/pvcdrom/properties-of-sunlight/sun-position-calculator
 
Where might I be going wrong?
 
Many thanks for a reply!
 
Andrew Theokas

 

   
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